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167

answers:

3

What is a platform-independent way of specifying the largest representable negative floating-point number?

We found an algorithm that broke when run on a PS3's SPU, but worked fine when compiled for the PPU:

float x = -FLT_MAX;
/* stuff */
if (x > 0.0f) {
    // If x is unchanged, code is executed on SPU
}

Essentially, is there a well-defined negative equivalent of FLT_MAX?

A: 

Check here. May be useful

Chubsdad
+1  A: 

You want std::numeric_limits::lowest(), but it is c++0x only, so not very cross platform at the moment.

You definitely don't want std::numeric_limits::min() - that is smallest magnitude, not furthest negative.

If you want something that will always be less than all other doubles, use -numeric_limits<double>::infinity().

njamesp
Upvoting, as we do essentially want a very large negative number that is guaranteed to be smaller than anything else.
Blair Holloway
+2  A: 

Without know what's in /* stuff */, I don't think your problem can be fully addressed here.

There's a good set of slides on the problems inherent in floating point calculation here: http://realtimecollisiondetection.net/pubs/GDC07_Ericson_Physics_Tutorial_Numerical_Robustness.ppt - there may be some hint for you in there as to the source of your problem.

IEEE 754 single precision floating point is not the same on the SPU as it is on the PPU - there's a full explanation in chapter 9 of the SPU ISA document available from http://cell.scei.co.jp/e_download.html which also includes the maximum magnitude of a single precision floating point number.

Jonathan
I'm accepting this as the answer -- after reading the linked document detailing the SPU architecture, it became apparent that `-FLT_MAX` wasn't going to work.
Blair Holloway
As an aside, the code in `/* stuff */` shouldn't matter, as `x` was only touched in certain conditions that weren't being met; `x` was unchanged by the time we check `x > 0.0f`, which was why there was much head-scratching when it passed!
Blair Holloway
Oh, I missed the comment inside the if block. Happy to hear that you've worked it out :)
Jonathan