views:

19

answers:

1

I have a master detail relationship between a person and its friends:

person

id name
-- ------
 1 Jones
 2 Smith
 3 Norris

friends

id personId friendName
-- -------- ----------
 1        1 Alice
 2        1 Bob
 3        1 Charly
 4        1 Deirdre
 5        2 Elenor

A person can have as many friends as he wants. I want to create a view that selects all persons together with the first three friends it finds; something like this:

id name   friend1 friend2 friend3
-- ----   ------- ------- -------
 1 Jones  Alice   Bob     Charly
 2 Smith  Elenor  <null>  <null>
 3 Norris <null>  <null>  <null>

How do I do this with standard SQL? (Microsoft SQL Server 2005).

+2  A: 
    SELECT p.Id, p.name,
            MAX(CASE RowNum
                WHEN 1 THEN
                 FriendName
                ELSE
                 NULL
             END) Friend1,
            MAX(CASE RowNum
                WHEN 2 THEN
                 FriendName
                ELSE
                 NULL
             END) Friend2,
            MAX(CASE RowNum
                WHEN 3 THEN
                 FriendName
                ELSE
                 NULL
             END) Friend3
     FROM   Person p
     LEFT   JOIN (SELECT id, PersonId, FriendName,
                        ROW_NUMBER() OVER(PARTITION BY PersonId ORDER BY id) RowNum
                 FROM   Friends) f
     ON     f.PersonId = p.Id
    GROUP  BY p.Id, p.Name

result:

1   Jones   Alice   Bob Charly
3   Norris  NULL    NULL    NULL
2   Smith   Elenor  NULL    NULL
Michael Pakhantsov
+1, the `else null` is redundant though, without no `when` matches, the case returns null by default
Andomar
Works like a charm! Thanks a lot a thousand times!!!
Dirk Moebius