To write a fuction that prints each element of a STL vector despite the type

Question

I tried with this piece of code but it didn't work

template <class T>
void display(vector<T> vec)
{
  vector<T>::iterator MyIter;
  for(MyIter=vec.begin();MyIter!=vec.end();MyIter++)
    cout<<*MyIter<<" ";
  cout<<endl;
}

I mean if there's a way of avoid making a function for each type T (int, char, string). I'm using only builtin types for T.

This is the error message when I compile the program

10 C:\Documents and Settings\ASPIRE\Desktop\perms.cpp expected `;' before "MyIter" 

Answer 1

Can you be more clear on how this code did not work?

It relies on the existence of T::operator<< - if that is not present for any instantiating type/class T that you use in your code, the code will not compile. For builtin types this code would work OK. If you are using this for vector of your own types then you would have to implement operator<< for each for this to work.

btw use ++MyIter, it's more efficient.

Answer 2

You are missing the typename infront of the variable definition MyIter i.e. it should be typename vector<T>::iterator MyIter;