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31

answers:

1

Let's say i acquire the name of a class that i made as a String. How can i Instantiate the class with the name contained in that string? I I know it will be derived from a certain parent class, but the actual class will vary.

+2  A: 

var instance : MyClass = Type.createInstance(Type.resolveClass("path.to.MyClass"), []);

Few notes:

  • resolveClass takes the full path (packages included) of the classe you need
  • createInstance takes as the second argument an array of values that are applied to the constructor. Those values must be in the exact number and must be passed even if they are optional (nulls are good in that case).
Franco Ponticelli