[Awk/Sed] How do i print word after regex but not a similar word?

Question

I want an awk or sed command to print the word after regexp.

I want to find the WORD after a WORD but not the WORD that looks similar.

The file looks like this:

 somethingsomething
 X-Windows-Icon=xournal
 somethingsomething
 Icon=xournal
 somethingsomething
 somethingsomething 

I want "xournal" from the one that say "Icon=xournal". This is how far i have come until now. I have tried an AWK string too but it was also unsuccessful.

cat "${file}" | grep 'Icon=' | sed 's/.*Icon=//' >> /tmp/text.txt

But i get both so the text file gives two xournal which i don't want.

Answer 1

Use ^ to anchor the pattern at the beginning of the line. And you can even do the grepping directly within sed:

sed -n '/^Icon=/ { s/.*=//; p; }' "$file" >> /tmp/text.txt

You could also use awk, which I think reads a little better. Using = as the field separator, if field 1 is Icon then print field 2:

awk -F= '$1=="Icon" {print $2}' "$file" >> /tmp/text.txt

Answer 2

This might be useful even though perl is not tagged. In case if you are interested in perl.this small program will do the task for you.

#!/usr/bin/perl -w

while(<>)
{
if(/Icon\=/i)
{
print $';
}
}

below is the output:

C:\Documents and Settings\Administrator>io.pl new2.txt
xournal
xournal

explanation:

while (<>) takes the input data from the file given as an argument on the command line while executing.

(/Icon\=/i) is the regex used in the if condition

$' will print the part of the line after the regex.