Hi,
I've put an image into my tableview cell in which the image is located in a certain URL.. My problem is that when my tableView already displays the data, then scrolling the tableview up & down, it will take some time or delay before it reacts to the scrolling..
I've found out the problem is into the image located in the URL and I need also to display each image in the tableview cell. Any idea how I can fix it? or to be optimize?
Here's my code:
- (UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath {
static NSString *CellIdentifier = @"Cell";
UITableViewCell *cell = [self.tableView dequeueReusableCellWithIdentifier:CellIdentifier];
if (cell == nil) {
cell = [[[UITableViewCell alloc] initWithStyle:UITableViewCellStyleSubtitle reuseIdentifier:CellIdentifier] autorelease];
}
// Set up the cell
NSUInteger row = [indexPath row];
cell.accessoryType = UITableViewCellAccessoryDisclosureIndicator;
NSArray *arrLocal = [m_list objectAtIndex:row];
if ([arrLocal count] > 0) {
cell.textLabel.text = [arrLocal objectAtIndex:2];
cell.textLabel.font = [UIFont boldSystemFontOfSize:14];
cell.detailTextLabel.text = [arrLocal objectAtIndex:3];
cell.detailTextLabel.font = [UIFont systemFontOfSize:12];
//sample url of the image: http://www.mysite.com/images/DealExtreme/2657_1_small.jpg
NSString *strTemp = [[NSString alloc] initWithString:@"http://www.mysite.com/"];
NSString *urlString = [strTemp stringByAppendingString: [arrLocal objectAtIndex:1]];
NSURL *url = [NSURL URLWithString:urlString];
UIImage *image = [UIImage imageWithData: [NSData dataWithContentsOfURL:url]];
cell.imageView.image = image;
[strTemp release];
}
return cell;
}