views:

67

answers:

2

Hi there,

I'm currently using boost::intrusive_ptr together with my GUI classes. Although this is more or less a convenience question, is there a proper way to get the typename of the current class? The reason I'm asking is that I have a macro for typedef'ing the different pointer types:

#define INTRUSIVE_PTR_TYPEDEFS(CLASSNAME) typedef boost::intrusive_ptr<CLASSNAME> Ptr; \
typedef boost::intrusive_ptr<const CLASSNAME> CPtr; \
typedef CLASSNAME* WeakPtr; \
typedef const CLASSNAME* CWeakPtr;

...

class Widget
{
public:
    INTRUSIVE_PTR_TYPEDEFS(Widget);
    ...
};

class Button : public Widget
{
public:
    INTRUSIVE_PTR_TYPEDEFS(Button);
    ...
};

It would be much more comfortable to have CLASSNAME automatically deduced so you could simply copy'n'paste it into the class body. I'm using the compiler shipped with Visual Studio 2010.

Thanks in advance!

A: 

Hmm, one idea I have is to call constructor and typename on this pointer... Another way could be to create a template metaprogram for creating classes, which will do the typedefs as well.

Gabriel Ščerbák
That's actually what I wanted to do, but after having a first glance at Boost.MPL, I couldn't find what I was looking for. Could you give me a hint on that?
Sebastian
+2  A: 

No, that's not possible to do in C++.

Johannes Schaub - litb