Hi !
I want to grep the username.
the command id gives the following.
id output is
uid=0(root) gid=0(root)
but i want the output as only root or who ever the user is.
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46answers:
2
+1
A:
That's not a grep, that's a cut:
$ id | cut -d '(' -f 2 | cut -d ')' -f 1
If you're doing this in a script (as a comment implies), you need to capture the output of the command properly. In bash, use:
USER=$(id | cut -d '(' -f 2 | cut -d ')' -f 1)
Many o(th|ld)er shells support the backtick syntax:
USER=`id | cut -d '(' -f 2 | cut -d ')' -f 1`
unwind
2010-09-15 11:17:43
when i use it in a script , it displays nothing #!/bin/bashUserid=id | cut -d '(' -f 2 | cut -d ')' -f 1echo $Userid
randeepsp
2010-09-15 11:34:47
A:
id -un
will directly print the name associated with the current effective user-id.
Diomidis Spinellis
2010-09-15 11:26:58