Greetings all,
in my application i use the following code:
bool HandleMessages()
{
MSG msg;
if (PeekMessage(&msg, NULL, 0, 0, PM_REMOVE))
{
if (msg.message == WM_QUIT)
return FALSE;
TranslateMessage(&msg);
DispatchMessage(&msg);
}
return true;
}
This is the standard code for message handling in windows i thought, but now when i try to run the program, i always get an Exception at the PeekMessage() call.
Exception message is
Unhandled exception at 0x57a10eed (msvcr100d.dll) in testing.exe: 0xC0000005: access violation while reading at Position 0x6666665c.
Im completely lost here, cant see why it would throw an exception. Anyone got a hint?
Call Stack:
msvcr100d.dll!__local_unwind2() + 0x48 Bytes Asm
msvcr100d.dll!_except_handler3() + 0xed Bytes Asm
Testing.exe!_except_handler4(_EXCEPTION_RECORD * ExceptionRecord, _EXCEPTION_REGISTRATION_RECORD * EstablisherFrame, _CONTEXT * ContextRecord, void * DispatcherContext) + 0x24 Bytes C
Testing.exe!_except_handler4(_EXCEPTION_RECORD * ExceptionRecord, _EXCEPTION_REGISTRATION_RECORD * EstablisherFrame, _CONTEXT * ContextRecord, void * DispatcherContext) + 0x24 Bytes C
Disassembly:
continue:
57CE0EEA lea esi,[esi+esi*2]
57CE0EED mov ecx,dword ptr [ebx+esi*4]
57CE0EF0 mov dword ptr [esp+0Ch],ecx
57CE0EF4 mov dword ptr [eax+0Ch],ecx
57CE0EF7 cmp dword ptr [ebx+esi*4+4],0
57CE0EFC jne _lu_continue (57CE0F15h)
57CE0EFE push 101h
57CE0F03 mov eax,dword ptr [ebx+esi*4+8]
57CE0F07 call _NLG_Notify (57CE0F55h)
57CE0F0C mov eax,dword ptr [ebx+esi*4+8]
57CE0F10 call _NLG_Call (57CE0F74h)