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131

answers:

3

I have a Java application that needs to connect via sockets to two different servers on two separate machines. One server has been configured to listen on IPv4 connections, while the other has been configured to listen on IPv6 connections.

Now, assuming "host1" is the machine name of the server listening on IPv4 connections, while "host2" is the machine name of the server listening on IPv6 connections. I need to get an Inet4Address for "host1" and an Inet6Address for "host2" to create a socket connection to each server, such as the following:

Inet4Address inet4 = (Inet4Address)InetAddress.getByName("host1");
InetSocketAddress soc4 = new InetSocketAddress(inet4, 7777);
...

Inet6Address inet6 = (Inet6Address)InetAddress.getByName("host2");
InetSocketAddress soc6 = new InetSocketAddress(inet6, 7777);
...

However, the JVM by default prefers to use IPv4 addresses over IPv6 addresses for backward compatibility reasons. So, in the above code, the first attempt to connect to "host1" succeeds, but the second attempt to connect to "host2" fails because InetAddress.getByName("host2") returns an Inet4Address instead of Inet6Address.

I understand that I can set the system property java.net.preferIPv6Addresses to true to prefer IPv6 addresses over IPv4, but this in turn causes the second attempt to connect to "host2" succeeds, but the first attempt to connect to "host1" failed(!) because InetAddress.getByName("host1") returns an Inet6Address instead of Inet4Address.

The system property java.net.preferIPv6Addresses is only being read once (see InetAddress line 212-218) and so it would have no effects even if I change its value back to false after setting it to true.

So what I can I do in this case? This seems like a common problem, so surely there has to be a way already to do it.

Note that I can of course use InetAddress.getByAddress() and supply each machine's IP address explicitly instead to get back an Inet4Address and Inet6Address, but I do not want to do this unless I really have to. So other solutions please.

Oh, I am using java 1.6.0_19 in case it matters.

Thanks!

+1  A: 

Unless you have a specific need for methods only available in Inet6Address or Inet4Address you shouldn't use these classes directly, instead use InetAddress.

This way you won't need to cast and risk to have a CCE.

In your case I don't really see good reasons to use specifically IPv6 or IPv4 classes.

Remember, IPv6 is compatible with IPv4, so you don't really have to worry when you use an IPv4 address with an IPv6 system.


Resources :

Colin Hebert
I do. As I said, the two servers are listening to IPv4 and IPv6 connections respectively. The casting I did in the sample code above was just to show that I wanted (and I need to) get an `Inet6Address` which I then need to pass to `InetSocketAddress` to connect to "host2" (passing an `Inet4Address` will cause a connection failure). So, even though I just use the superclass `InetAddress` all the time, underneath it is actually either `Inet4Address` or `Inet6Address`, isn't it? And in this case, I wanted to make it obvious the problem I am having by doing the casting explicitly.
Yes, it will still `Inet4Address` only or `Inet6Address`, and what is the problem with it? IPv6 is compatible with IPv4 there shouldn't be any problem.
Colin Hebert
Well, I'm not sure, because that's not what I experienced. I can't use an `Inet6Address` (or `InetAddress` if you like) to connect to the server listening on IPv4 connection - I get a connection failure. This: `new InetSocketAddress(InetAddress.getByName("host1"), 7777)` with `InetAddress.getByName("host1")` returning an Inet6Address/InetAddress, won't work. But if `InetAddress.getByName("host1")` returns an `Inet4Address/InetAddress`, it would work.
I don't really see the problem here, but after looking at this article : http://download.oracle.com/javase/1.4.2/docs/guide/net/ipv6_guide/ It seems that it should work without any cast or whatsoever
Colin Hebert
I don't know if it is my machine that is wrong, but I still couldn't use InetAddress (which is Inet6Address underneath) to connect to the server listening on IPv4 connections. In case it matters, the client and server machines are all Windows XP.
A: 

Have you tried with Inet6Address.getAllByName("host2").

this must return IPv6 addres of host, that can be used to create socket.

krishna
`Inet6Address` doesn't have a specific implementation of `getAllByName(String)`, so calling `Inet6Address.getAllByName(String)` is really the same as calling the parent's static method `InetAddress.getAllByName(String)`.
+1  A: 
static Inet6Address getInet6AddressByName(String host) throws UnknownHostException, SecurityException
{
    for(InetAddress addr : InetAddress.getAllByName(host))
    {
        if(addr instanceof Inet6Address)
            return (Inet6Address)addr;
    }
    throw new UnknownHostException("No IPv6 address found for " + host);
}
Andrew Duffy