Passing an object to a function taking pointer as parameter

Question

How does it work when I only have an object but my function takes a pointer to that type of object.

Someoclass test1;

SomeFunction( Someclass*)
{
    //does something
};

Answer 1

You pass the address of the object.

SomeFunction(&test1);

Answer 2

To call the function, you need to use the address of operator (&). So in your case:

Someclass test1;

SomeFunction(&test1);

If you are asking how pointers work, there's a detailed explanation here.