Erasing from a std::vector while doing a for each?

Question

The proper way to iterate is to use iterators. However, I think by erasing, the iterator is invalidated.

Basically what I want to do is:

for(iterator it = begin; it != end; ++it)
{
    if(it->somecondition() )
    {
     erase it
    }

}

How could I do this without v[i] method?

Thanks

struct RemoveTimedEvent
{
    bool operator()(const AguiTimedEvent& pX, AguiWidgetBase* widget) const 
    {
        return pX.getCaller() == widget;
    }
};

void AguiWidgetContainer::clearTimedEvents( AguiWidgetBase* widget )
{
    std::vector<AguiTimedEvent>::iterator it = std::remove_if(timedEvents.begin(),
        timedEvents.end(), RemoveTimedEvent());
    timedEvents.erase(it, timedEvents.end());

}

Answer 1

erase() returns a new iterator:

for(iterator it = begin; it != end;)
{
    if (it->somecondition())
    {
        it = vec.erase(it);
    }
    else
    {
        ++it;
    }
}

A better method might be to combine std::remove_if and erase(). You change from being O(N²) (every element gets erased) to O(N):

iterator it = std::remove_if(begin, end, pred);
vec.erase(it, vec.end());

Where pred is you predicate, such as:

struct predicate // do choose a better name
{
    bool operator()(const T& pX) const // replace T with your type
    {
        return pX.somecondition();
    }
};

iterator it = std::remove_if(begin, end, predicate());
vec.erase(it, vec.end());

In your case, you can make it pretty general:

class remove_by_caller
{
public:
    remove_by_caller(AguiWidgetBase* pWidget) :
    mWidget(pWidget)
    {}

    // if every thing that has getCaller has a base, use that instead
    template <typename T> // for now a template
    bool operator()(const T& pX) const
    {
        return pX.getCaller() == mWidget;
    }

private:
    AguiWidgetBase* mWidget;
};

std::vector<AguiTimedEvent>::iterator it =
    std::remove_if(timedEvents.begin(), timedEvents.end(), remove_by_caller(widget));
timedEvents.erase(it, timedEvents.end());

Note lambda's exist to simplify this process, both in Boost and C++0x.