I'm desperately trying to make sense of Arel, mostly because I hate dealing with SQL; I was doing so well, but I've hit a wall.
I've been working in Rails 3.0.0, and I'm trying to make a complex query with some math in it. The real case is rather more complex, but I've simplified a bit. In my example, I have a table with a particular string field, and I want a count of all the records, as well as a count for each of two possible values of that field, grouped by a foreign id.
Under Rails 3.0.0, I can do this (console commands):
t = Arel::Table.new(:some_thingies)
e = t .project(t[:foreign_id], t[:foreign_id].count.as('all_count')) .group(t[:foreign_id])
c = t.where(t[:some_field].eq('type1')).project(t[:foreign_id], t[:foreign_id].count.as('type1_count')).group(t[:foreign_id])
x = e
x = x.join(c).on(e[:foreign_id].eq(c[:foreign_id]))
and at this point I can do do x.to_sql and... well, I'm not entirely sure it's right, but the results look right, aside from having the foreign_id column twice.
SELECT
`some_thingies_external`.`foreign_id`,
`some_thingies_external`.`all_count`,
`some_thingies_external_2`.`foreign_id`,
`some_thingies_external_2`.`type1_count`
FROM
(SELECT
`some_thingies`.`foreign_id`, COUNT(`some_thingies`.`foreign_id`)
AS `type1+count`
FROM `some_thingies`
GROUP BY `some_thingies`.`foreign_id`) `some_thingies_external`
INNER JOIN
(SELECT `some_thingies`.`foreign_id`, COUNT(`some_thingies`.`foreign_id`)
AS `type1_count`
FROM `some_thingies`
WHERE `some_thingies`.`type` = 'type1'
GROUP BY `some_thingies`.`foreign_id`) `some_thingies_external_2`
ON `some_thingies_external`.`foreign_id` = `some_thingies_external_2`.`foreign_id`
So far so good. However, when I try to join in a second set of counts like this:
i = t.where(t[:some_field].eq('type2')).project(t[:foreign_id], t[:foreign_id].count.as('type2_count')).group(t[:foreign_id])
x = x.join(i).on(e[:foreign_id].eq(i[:foreign_id]))
it just hangs up, leading me to think I'm hitting this bug
(btw I've got more counts to add in, and ideally 'some_thingies' should itself be an arel object representing more filtering on which thingies we're counting... but I digress...)
So, I decided to try out the latest edge Arel and Rails, and bumped up my gems accordingly:
gem 'rails', :git => 'git://github.com/rails/rails.git'
gem 'rack', :git => 'git://github.com/rack/rack.git'
gem 'arel', :git => 'http://github.com/brynary/arel.git'
and now when I try to do do the first join, it fails miserably:
ruby-1.9.2-preview3 > x = x.join(c).on(e[:foreign_id].eq(c[:foreign_id]))
NoMethodError: undefined method `[]' for #<Arel::SelectManager:0x00000104311e38>
from (irb):12
from /Users/stephan/.rvm/gems/ruby-1.9.2-preview3/bundler/gems/rails-c42ea2172eb9/railties/lib/rails/commands/console.rb:44:in `start'
from /Users/stephan/.rvm/gems/ruby-1.9.2-preview3/bundler/gems/rails-c42ea2172eb9/railties/lib/rails/commands/console.rb:8:in `start'
from /Users/stephan/.rvm/gems/ruby-1.9.2-preview3/bundler/gems/rails-c42ea2172eb9/railties/lib/rails/commands.rb:33:in `<top (required)>'
from script/rails:6:in `require'
from script/rails:6:in `<main>'
This doesn't seem like a bug in Arel - if anything, it seems more like the fact that it worked before is the bug. I think I just don't know what an Arel::SelectManager is and what to do with it. It seemed like I was doing so well, but I really don't get what is going on.
Do I need to somehow make a new table based on the SelectManager I've got? Or am doing something wrong in my configuration which makes the [] syntax fail? Or do I just totally fail to understand what Arel does? I still don't quite get what I'm supposed to do with Arel::Rows, but I suppose I'll get the hang of that; and I suspect I can get rid of the extra foreign key in the results with a project()...
But I'm still pretty lost. Haaaaalp!
p.s. does 'railties' rhyme with 'frailties,' or with 'mail guys'?