Hey fellas,
What is a neat way to hold pairs of strings which are not necessarily key-values (might have duplicate keys), for a small collection? List[List[String]] works obviously but looks dirty.
Cheers
Parsa
+12
A:
List[(String,String)] is the standard solution:
scala> List(("foo","bar"), ("foo","baz"))
res1: List[(java.lang.String, java.lang.String)] = List((foo,bar), (foo,baz))
larsmans
2010-10-17 12:15:34
Exactly! The nice thing about tuples is that equality, pattern matching, etc. works as one would expect. `("foo", "bar") == ("foo", "bar")` returns `true`, for example.
soc
2010-10-17 12:27:42
You also get lexicographic ordering of pairs, which is an extremely nice freebie.
Dave Griffith
2010-10-17 13:53:57
I came across this nice tuple trick yesterday: http://goo.gl/MT6J. It makes a good use of the fact that all the tuple classes have instances of `Ordering` trait defined for them.
missingfaktor
2010-10-17 15:30:36
+10
A:
Tuples are the ideal data structure to represent pairs.
So use a list of (String, String) tuples.
sepp2k
2010-10-17 12:17:20