rendering a partial from a haml file

Question

I have a simple sinatra app that uses haml and sass for the views. One of the views (located in the views folder) is a partial for my navigation menu. I am trying to render it from index.haml but I get the following error: wrong number of arguments (1 for 2)

I am trying to render it with the following lines in index.haml

.navigation
  = render :partial => "nav"

Answer 1

What are you trying works in rails! Sinatra has no partial method. An implementation of partial on Sinatra looks like this (source gist) from github:

module Haml
  module Helpers
    def partial(template, *args)
      template_array = template.to_s.split('/')
      template = template_array[0..-2].join('/') + "/_#{template_array[-1]}"
      options = args.last.is_a?(Hash) ? args.pop : {}
      options.merge!(:layout => false)
      if collection = options.delete(:collection) then
        collection.inject([]) do |buffer, member|
          buffer << haml(:"#{template}", options.merge(:layout =>
          false, :locals => {template_array[-1].to_sym => member}))
        end.join("\n")
      else
        haml(:"#{template}", options)
      end
    end
  end
end

Including this method, you may call partial in your .haml files, like
= partial("partial_name")

If you want to render a view in an other view syntax is
= render(:haml,:'rel_path_to_view',:locals => {:optional => option})

Notice the syntax differences between rails and sinatra regarding render method!