Why this code doesn't work?
public function get($key) {
return isset($_SESSION[$key]) ? &$_SESSION[$key] : false;
}
Error
Parse error: syntax error, unexpected '&' in C:\Arquivos de programas\EasyPHP-5.3.3\www\myphpblog\code\sessionstorage.class.php on line 12
Thank you.
A ternary operator is really three expressions, e.g. expr1 ? expr2 : expr3;
See the Notes in Returning References:
If you try to return a reference from a function with the syntax:
return ($this->value);this will not work as you are attempting to return the result of an expression, and not a variable, by reference. You can only return variables by reference from a function - nothing else.
The syntax for returning a reference in PHP is &<function name>(){ return <referece> }
Also, Only variable references should be returned by reference
So, you should probably rewrite it:
function &get($key) {
$a = false;
if( isset($_SESSION[$key]) )
return $_SESSION[ $key ];
return $a;
}