$sql="SELECT * FROM Reg_Stud WHERE Username='$var1' AND RegID=$var2 ";
this is the code...
i tried the input
Username =anything' OR 'x'='x
ID =12 or 1=1
no sign of sql injection...but when i just give the 1st argument and end it by commenting the rest...it gives sql error i.e anything' OR 'x'='x;--