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359

answers:

2

I'm aware of the range iterators in boost, and as for this reference, it seems there should be an easy way of doing what I want, but it's not obvious to me.

Say I want to represent a numerical range, 0 to 100 (inclusive or not), say range(0,100). I would like to do something like:

for_each(range<int>(0,100).begin(), range<int>(0,100).end(), do_something);

where do_something is a functor. This iterators shouldn't have the overhead of having an underneath vector or something like this, but to just offer a sequence of integers. Is this possible with the range implementation in boost? Possible at all with normal, standard STL iterators?

+7  A: 

boost::counting_iterator

#include <boost/iterator/counting_iterator.hpp>

std::for_each( boost::counting_iterator<int>(0),
               boost::counting_iterator<int>(100),
               do_something );
Vadim Ferderer
Thank you! Exactly what I wanted... Don't know how I missed it searching through the boost libraries... :)
Diego Sevilla
+4  A: 

Yes, it is possible. It just seems boost::range doesn't have support for it out of the box, but you can

  • use boost::counting_iterator, which does just what you want
  • implement a number-like object whose operator*() would return a number, and use that as an iterator for range
jpalecek