I would recommend building a user defined function that calculates the date difference in business hours according to your rules.
SELECT
Id,
MIN(Date) DateStarted,
MAX(Date) DateCompleted,
dbo.udfDateDiffBusinessHours(MIN(Date), MAX(Date)) ReactionTime
FROM
Incident
GROUP BY
Id
I'm not sure where your Overdue
value comes from, so I left it off in my example.
In a function you can write way more expressive SQL than in a query, and you don't clog your query with business rules, making it hard to maintain.
Also a function can easily be reused. Extending it to include support for holidays (I'm thinking of a Holidays
table here) would not be too hard. Further refinements are possible without the need to change hard to read nested SELECT/CASE WHEN constructs, which would be the alternative.
If I have time today, I'll look into writing an example function.
EDIT: Here is something with bells and whistles, calculating around weekends transparently:
ALTER FUNCTION dbo.udfDateDiffBusinessHours (
@date1 DATETIME,
@date2 DATETIME
) RETURNS DATETIME AS
BEGIN
DECLARE @sat INT
DECLARE @sun INT
DECLARE @workday_s INT
DECLARE @workday_e INT
DECLARE @basedate1 DATETIME
DECLARE @basedate2 DATETIME
DECLARE @calcdate1 DATETIME
DECLARE @calcdate2 DATETIME
DECLARE @cworkdays INT
DECLARE @cweekends INT
DECLARE @returnval INT
SET @workday_s = 510 -- work day start: 8.5 hours
SET @workday_e = 960 -- work day end: 16.0 hours
-- calculate Saturday and Sunday dependent on SET DATEFIRST option
SET @sat = CASE @@DATEFIRST WHEN 7 THEN 7 ELSE 7 - @@DATEFIRST END
SET @sun = CASE @@DATEFIRST WHEN 7 THEN 1 ELSE @sat + 1 END
SET @calcdate1 = @date1
SET @calcdate2 = @date2
-- @date1: assume next day if start was after end of workday
SET @basedate1 = DATEADD(dd, 0, DATEDIFF(dd, 0, @calcdate1))
SET @calcdate1 = CASE WHEN DATEDIFF(mi, @basedate1, @calcdate1) > @workday_e
THEN @basedate1 + 1
ELSE @calcdate1
END
-- @date1: if Saturday or Sunday, make it next Monday
SET @basedate1 = DATEADD(dd, 0, DATEDIFF(dd, 0, @calcdate1))
SET @calcdate1 = CASE DATEPART(dw, @basedate1)
WHEN @sat THEN @basedate1 + 2
WHEN @sun THEN @basedate1 + 1
ELSE @calcdate1
END
-- @date1: assume @workday_s as the minimum start time
SET @basedate1 = DATEADD(dd, 0, DATEDIFF(dd, 0, @calcdate1))
SET @calcdate1 = CASE WHEN DATEDIFF(mi, @basedate1, @calcdate1) < @workday_s
THEN DATEADD(mi, @workday_s, @basedate1)
ELSE @calcdate1
END
-- @date2: assume previous day if end was before start of workday
SET @basedate2 = DATEADD(dd, 0, DATEDIFF(dd, 0, @calcdate2))
SET @calcdate2 = CASE WHEN DATEDIFF(mi, @basedate2, @calcdate2) < @workday_s
THEN @basedate2 - 1
ELSE @calcdate2
END
-- @date2: if Saturday or Sunday, make it previous Friday
SET @basedate2 = DATEADD(dd, 0, DATEDIFF(dd, 0, @calcdate2))
SET @calcdate2 = CASE DATEPART(dw, @calcdate2)
WHEN @sat THEN @basedate2 - 0.00001
WHEN @sun THEN @basedate2 - 1.00001
ELSE @date2
END
-- @date2: assume @workday_e as the maximum end time
SET @basedate2 = DATEADD(dd, 0, DATEDIFF(dd, 0, @calcdate2))
SET @calcdate2 = CASE WHEN DATEDIFF(mi, @basedate2, @calcdate2) > @workday_e
THEN DATEADD(mi, @workday_e, @basedate2)
ELSE @calcdate2
END
-- count full work days (subtract Saturdays and Sundays)
SET @cworkdays = DATEDIFF(dd, @basedate1, @basedate2)
SET @cweekends = @cworkdays / 7
SET @cworkdays = @cworkdays - @cweekends * 2
-- calculate effective duration in minutes
SET @returnval = @cworkdays * (@workday_e - @workday_s)
+ @workday_e - DATEDIFF(mi, @basedate1, @calcdate1)
+ DATEDIFF(mi, @basedate2, @calcdate2) - @workday_e
-- return duration as an offset in minutes from date 0
RETURN DATEADD(mi, @returnval, 0)
END
The function returns a DATETIME
value meant as an offset from date 0 (which is "1900-01-01 00:00:00"
). So for example a timespan of 8:00 hours would be "1900-01-01 08:00:00"
and 25 hours would be "1900-01-02 01:00:00"
. The function result is the time difference in business hours between two dates. No special handling/support for overtime.
SELECT dbo.udfDateDiffBusinessHours('2003-04-29 15:00:00', '2003-04-30 11:00:00')
--> 1900-01-01 03:30:00.000
SELECT dbo.udfDateDiffBusinessHours('2003-04-30 14:00:00', '2003-05-01 14:00:00')
--> 1900-01-01 07:30:00.000
The function assumes the start of the next available work day (08:30 h) when the @date1
is off-hours, and the end of the previous available work day (16:00 h) when @date2
is off-hours.
"next/previous available" means:
- if
@date1
is '2009-02-06 07:00:00'
(Fri), it will become '2009-02-06 08:30:00'
(Fri)
- if
@date1
is '2009-02-06 19:00:00'
(Fri), it will become '2009-02-09 08:30:00'
(Mon)
- if
@date2
is '2009-02-09 07:00:00'
(Mon), it will become '2009-02-06 16:00:00'
(Fri)
- if
@date2
is '2009-02-09 19:00:00'
(Mon), it will become '2009-02-09 16:00:00'
(Mon)