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How to implement 'open file location' behaviour programmatically (c++ builder)

Answer 1

A:

You should use the ShellExecute() function. Something like this should work:

ShellExecute(handle, "explore", @"C:\WINDOWS", NULL, NULL, SW_SHOWNORMAL);

Scott W 2009-02-28 22:59:01

I think that only works for folders, not files. I want to explore _and_ select the file.

MrVimes 2009-02-28 23:22:39

I figured out the command line for this... explorer /select,(filename) so I now need to figure out how to run that shell command

MrVimes 2009-02-28 23:25:43

Answer 2

+1 A:

Try launching explorer.exe with option /select,<selected file path>. Something like:

explorer /n, /select,c:\windows\notepad.exe

It should open new explorer window with c:\windows folder open and notepad.exe selected.

Tomek Szpakowicz 2009-02-28 23:16:04

can I run this using shellexecute()? I can run it on the command line and it works, but when I run in shellexecute nothing happens. ShellExecute(Form1->Handle,NULL,String("explorer.exe /n, /select," + FileName).c_str(),NULL,NULL,SW_SHOWNORMAL);

MrVimes 2009-02-28 23:38:39

OK I'm tearing my hair out trying to run that in an application so I guess I'll ask a fresh question on stackoverflow.

MrVimes 2009-03-01 00:10:14

What about: ShellExecute(Form1->Handle,"open","c:\\windows\\explorer.exe", String("/n, /select," + FileName).c_str(),NULL,SW_SHOWNORMAL);Or use one of _spawn functions. See documentation for more.

Tomek Szpakowicz 2009-03-01 00:12:45

Answer 3

A:

It's a Win2 FAQ for more than 16 years (!)

Search on Google Groups before posting a so basic question where the C code has been posted 25000 times...

2009-03-01 11:37:55

Very helpful. Thanks.

MrVimes 2009-03-09 15:46:56

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How to implement 'open file location' behaviour programmatically (c++ builder)

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