views:

1417

answers:

6

Here is what I currently have so far:

void WriteHexToFile( std::ofstream &stream, void *ptr, int buflen, char *prefix )
{
    unsigned char *buf = (unsigned char*)ptr;

    for( int i = 0; i < buflen; ++i ) {
     if( i % 16 == 0 ) {
      stream << prefix;
     }

     stream << buf[i] << ' ';
    }
}

I've tried doing stream.hex, stream.setf( std::ios::hex ), as well as searching Google for a bit. I've also tried:

stream << stream.hex << (int)buf[i] << ' ';

But that doesn't seem to work either.

Here is an example of some output that it currently produces:

Í Í Í Í Í Í Í Í Í Í Í Í Í Í Í Í 
Í Í Í Í Í Í Í Í Í Í Í Í Í Í Í Í 
Í Í Í Í Í Í Í Í Í Í Í Í Í Í Í Í 
Í Í Í Í Í Í Í Í Í Í Í Í Í Í Í Í 
Í Í Í Í Í Í Í Í Í Í Í Í Í Í Í Í 
Í Í Í Í Í Í Í Í Í Í Í Í Í Í Í Í

I would like the output to look like the following:

FF EE DD CC BB AA 99 88 77 66 55 44 33 22 11 00
FF EE DD CC BB AA 99 88 77 66 55 44 33 22 11 00
FF EE DD CC BB AA 99 88 77 66 55 44 33 22 11 00
FF EE DD CC BB AA 99 88 77 66 55 44 33 22 11 00
FF EE DD CC BB AA 99 88 77 66 55 44 33 22 11 00
FF EE DD CC BB AA 99 88 77 66 55 44 33 22 11 00
+3  A: 
char upperToHex(int byteVal)
{
    int i = (byteVal & 0xF0) >> 4;
    return nibbleToHex(i);
}

char lowerToHex(int byteVal)
{
    int i = (byteVal & 0x0F);
    return nibbleToHex(i);
}

char nibbleToHex(int nibble)
{
    const int ascii_zero = 48;
    const int ascii_a = 65;

    if((nibble >= 0) && (nibble <= 9))
    {
        return (char) (nibble + ascii_zero);
    }
    if((nibble >= 10) && (nibble <= 15))
    {
        return (char) (nibble - 10 + ascii_a);
    }
    return '?';
}

More code here.

McDowell
A: 
SurDin
+5  A: 
#include <iostream>
using namespace std;
int main() {
    char c = 123;
    cout << hex << int(c) << endl;
}

Edit: with zero padding:

#include <iostream>
#include <iomanip>
using namespace std;
int main() {
    char c = 13;
    cout << hex << setw(2) << setfill('0') << int(c) << endl;
}
anon
Won't that just output it to the console?
kitchen
Could you explain why that should work any differently from using stream.hex, like the asker already tried?
Rob Kennedy
I find the 'hex' stream modifier a bit of a pain. If you are outputting other types you have to keep switching the stream back (using 'dec' for example) and as far as I know, it doesn't do leading zeros.
Arnold Spence
@kitchen - replace cout with your own stream.
anon
@rob because the OP's code is wrong?
anon
@Neil: It worked, but what's the difference between using ofstream.hex and std::hex?
kitchen
OK, I'll explain it myself. Using stream.hex prints the value of the member-function pointer ostream::hex. (For me the value is 8.) Then it prints the integer value of the character in decimal.
Rob Kennedy
@rob the hex manipul;ator is not a member of the stream class. The hex you are printing is acually an enumeration value
anon
You might want to use unsigned(c) instead of int(c) if c<0.
Mr.Ree
mrree better (int)(unsigned char)c :)
Johannes Schaub - litb
And this is why I *love* C++ streams: cout << hex << setw(2) << setfill('0') << int(c) << endl is just *so* much clearer than printf("%02x", c) ;-) I know its typesafe(er) but couldn't they have dreamed up something less grotesque?
RBerteig
Clarity is a question of point of view... I don't think printf("%02x", c) can be considered as "clear"
Edouard A.
Mr.Ree
+3  A: 

You simply need to configure your stream once:

stream << std::hex << std::setfill('0') << std::setw(2)
Edouard A.
+1  A: 

Try:

#include <iomanip>
....
stream << std::hex << static_cast<int>(buf[i]);
Martin York
+1  A: 

You can also do it using something a bit more old-fashioned:

char buffer[3];//room for 2 hex digits and \0
sprintf(buffer,"%02X ",onebyte);
Mnebuerquo