During the day I am a Java developer, but at night I try stopping crime as a PHP superhero. My weapon of choice is symfony. We can say that I am training to be a superhero.
In Java, I use log4J, a logging framework. In Log4j you can do something like this:
if (log.isDebug()) {
// do some expensive operation that should only be displayed if DEBUG is turned on
}
In reading some symfony examples, I am unable to find a way to determine if DEBUG logging is activated in the current class context. Is there a way to do this?
if (--need something here--) {
$this->logMessage('Expensive operation return value: '.expensiveFunction(), 'debug');
}