How do I get the unix find command to print out the file size with the file name?

Question

If I issue the find command as follows:

$find . -name *.ear

It prints out:

./dir1/dir2/earFile1.ear
./dir1/dir2/earFile2.ear
./dir1/dir3/earFile1.ear

What I want to 'print' to the command line is the name and the size:

./dir1/dir2/earFile1.ear  5000 KB
./dir1/dir2/earFile2.ear  5400 KB
./dir1/dir3/earFile1.ear  5400 KB

Answer 1

find . -name "*.ear" -exec ls -l {} \;

Answer 2

You could try this:

find. -name *.ear -exec du {} \;

This will give you the size in bytes. But the du command also accepts the parameters -k for KB and -m for MB. It will give you an output like

5000  ./dir1/dir2/earFile1.ear
5400  ./dir1/dir2/earFile2.ear
5400  ./dir1/dir3/earFile1.ear

Answer 3

You could use something like:

find . -name *.ear | xargs du -h

although it won't give the precise output you're looking for.

Answer 4

find . -name "*.ear" | xargs ls -sh

Answer 5

a simple solution is to use the -ls option in find:

find . -name \*.ear -ls

That gives you each entry in the normal "ls -l" format. Or, to get the specific output you seem to be looking for, this:

find . -name \*.ear -printf "%p\t%k KB\n"

Which will give you the filename followed by the size in KB.

Answer 6

You need to use -exec or -printf. Printf works like this:

find . -name *.ear -printf "%p %k KB\n"

-exec is more powerful and lets you execute arbitrary commands - so you could use a version of 'ls' or 'wc' to print out the filename along with other information. 'man find' will show you the available arguments to printf, which can do a lot more than just filesize.

[edit] -printf is not in the official POSIX standard, so check if it is supported on your version. However, most modern systems will use GNU find or a similarly extended version, so there is a good chance it will be implemented.

Answer 7

find . -name '*.ear' -exec ls -lh {} \;

just the h extra from jer.drab.org's reply. saves time converting to MB mentally ;)

Answer 8

Using gnu find, I think this is what you want. It finds all real files and not directories (-type f), and for each one prints the filename (%p), a tab (\t), the size in kilobytes (%k), the suffix " KB", and then a newline (\n).

find . -type f -printf '%p\t%k KB\n'

If the printf command doesn't format things the way you want, you can use exec, followed by the command you want to execute on each file. Use {} for the filename, and terminate the command with a semicolon (;). On most shells, all three of those characters should be escaped with a backslash.

Here's a simple solution that finds and prints them out using "ls -lh", which will show you the size in human-readable form (k for kilobytes, M for megabytes):

find . -type f -exec ls -lh {} \;

As yet another alternative, "wc -c" will print the number of characters (bytes) in the file:

find . -type f -exec wc -c {} \;

Answer 9

Awk can fix up the output to give just what the questioner asked for. On my Solaris 10 system, find -ls prints size in KB as the second field, so:

% find . -name '*.ear' -ls | awk '{print $2, $11}'
5400 ./dir1/dir2/earFile2.ear
5400 ./dir1/dir2/earFile3.ear
5400 ./dir1/dir2/earFile1.ear

Otherwise, use -exec ls -lh and pick out the size field from the output. Again on Solaris 10:

% find . -name '*.ear' -exec ls -lh {} \; | awk '{print $5, $9}'
5.3M ./dir1/dir2/earFile2.ear
5.3M ./dir1/dir2/earFile3.ear
5.3M ./dir1/dir2/earFile1.ear

Answer 10

Unix find command options with practical examples

Scripter

Answer 11

:-)

$ find . -name "test*" -exec du -sh {} \;
4.0K    ./test1
0       ./test2
0       ./test3
0       ./test4
$

Regards,

scripter