I have a list and I want to remove a single element from it. How can I do this?
I've tried looking up what I think the obvious names for this function would be in the reference manual and I haven't found anything appropriate.
I have a list and I want to remove a single element from it. How can I do this?
I've tried looking up what I think the obvious names for this function would be in the reference manual and I haven't found anything appropriate.
I don't know R at all, but a bit of creative googling led me here: http://tolstoy.newcastle.edu.au/R/help/05/04/1919.html
The key quote from there:
I do not find explicit documentation for R on how to remove elements from lists, but trial and error tells me
myList[[5]] <- NULL
will remove the 5th element and then "close up" the hole caused by deletion of that element. That suffles the index values, So I have to be careful in dropping elements. I must work from the back of the list to the front.
A response to that post later in the thread states:
For deleting an element of a list, see R FAQ 7.1
And the relevant section of the R FAQ says:
... Do not set x[i] or x[[i]] to NULL, because this will remove the corresponding component from the list.
Which seems to tell you (in a somewhat backwards way) how to remove an element.
Hope that helps, or at least leads you in the right direction.
If you don't want to modify the list in-place (e.g. for passing the list with an element removed to a function), you can use indexing: negative indices mean "don't include this element".
x <- list("a", "b", "c", "d", "e"); # example list
x[-2]; # without 2nd element
x[-c(2, 3)]; # without 2nd and 3rd
Also, logical index vectors are useful:
x[x != "b"]; # without elements that are "b"
This works with dataframes, too:
df <- data.frame(number = 1:5, name = letters[1:5])
df[df$name != "b", ]; # rows without "b"
df[df$number %% 2 == 1, ] # rows with odd numbers only
Removing Null elements from a list in single line :
x=x[-(which(sapply(x,is.null),arr.ind=TRUE))]
Cheers