views:

1265

answers:

4

I am trying to json_encode an array, which is what returns from a Zend_DB query. var_dump gives: (Manually adding 0 member does not change the picture).

array(3) {
  [1]=>
  array(3) {
    ["comment_id"]=>
    string(1) "1"
    ["erasable"]=>
    string(1) "1"
    ["comment"]=>
    string(6) "test 1"
  }
  [2]=>
  array(3) {
    ["comment_id"]=>
    string(1) "2"
    ["erasable"]=>
    string(1) "1"
    ["comment"]=>
    string(6) "test 1"
  }
  [3]=>
  array(3) {
    ["comment_id"]=>
    string(1) "3"
    ["erasable"]=>
    string(1) "1"
    ["comment"]=>
    string(6) "jhghjg"
  }
}

The encoded string looks:

{"1":{"comment_id":"1","erasable":"1","comment":"test 1"},
 "2":{"comment_id":"2","erasable":"1","comment":"test 1"},
 "3":{"comment_id":"3","erasable":"1","comment":"jhghjg"}}

While I need it as: [{"comment_id":"1","erasable":"1","comment":"test 1"}, {"comment_id":"2","erasable":"1","comment":"test 1"}, {"comment_id":"3","erasable":"1","comment":"jhghjg"}]

As the php.ini/json__encode documentation says it should. Any ideas?

A: 

A common way to test for a traditional, continuous array in php is to check for an index '0'. Try adding that to your array, it'll probably considering it an array instead of hashmap.

Richard Levasseur
+5  A: 

How are you setting up your initial array?

If you set it up like:

array(
 "1" => array(...),
 "2" => array(...),
);

then you don't have an array with numeric indexes but strings, and that's converted to an object in JS world. This can happen also if you don't set a strict order (i.e. starting at 0 instead of 1).

This is a shot in the dark, however, because I can't see your original code: try setting your array without using keys at all in the first place:

array(
 array(...),
 array(...),
);
Seb
+1 # an array not starting with 0 for its key isn't an array. phps fault though for having a weird bastard lovechild of array/hash that works properly as neither.
Kent Fredric
The code is what returns as a Zend_DB query result
Itay Moav
Like I said, that doesn't make it an array, that makes it a hash with a numeric key, which just *happens* in this case to be close to 0 at the start because thats what the data in the database has.
Kent Fredric
Translation: what you want is logically impossible.
Kent Fredric
+1 to Kent... wish I could upvote your comments... instead, I upvoted your answer :)
Seb
+1  A: 

Added information that expands on Seb's answer.

php > print json_encode( array( 'a', 'b', 'c' ) ) ;
["a","b","c"]
php > print json_encode( array( 0 => 'a',  1 => 'b', 2 => 'c' ) ) ;
["a","b","c"]
php > print json_encode( array( 1 => 'a',  2 => 'b', 3 => 'c' ) ) ;
{"1":"a","2":"b","3":"c"}
php >

Note: its formatting it this way with good cause:

If you were to send

{"1":"a","2":"b","3":"c"}

as

["a","b","c"]

When you did $data[1] in Php you would get back "a", but on the JavaScript side, you would get back "b" .

Kent Fredric
A: 

i had a similar problem, got it to work after adding '' (single quotes) around the json_encode string. Following from my js file:

var myJsVar  = <?php echo json_encode($var); ?> ;    -------> NOT WORKING  
var myJsVar = '<?php echo json_encode($var); ?>' ;    -------> WORKING
harry