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Question

Answer 1

+4 A:

$content = file_get_contents('http://example.com/image.php');
file_put_contents('/my/folder/flower.jpg', $content);

soulmerge 2009-04-07 06:55:10

The page is holding an animated gif image. A file is stored into the folder as flower.gif .But it is blank.No image show.any solution?

riad 2009-04-07 07:07:47

Turn on error_reporting(E_ALL|E_STRICT) and check the return value of file_get_contents(), then you should get a reasonable error message.

soulmerge 2009-04-07 07:12:19

Perhaps the site admin has forbidden outside referrals. In that case you can try stream_context_create() and set the appropriate HTTP headers. http://us2.php.net/manual/en/function.stream-context-create.php

Calvin 2009-04-07 07:18:36

urlencode('http://example.com/image.php') == 'http%3A%2F%2Fexample.com%2Fimage.php', obviously not what you want. Also file is binary, proper flag needs to be set.

vartec 2009-04-07 07:19:27

thanks for the urlencode() hint. As for the binary flag: That one is available in PHP 6 only.

soulmerge 2009-04-07 07:23:45

Thanks all, it’s working fine now. But can anybody help me to do it automated. I mean when a new image come that URL 'http://example.com/image.php' my script will automatically fetch the image and store it to my directory?

riad 2009-04-07 08:19:58

This is another question and it had been asked some days ago on SO, just try to search it.

soulmerge 2009-04-07 11:58:47

Answer 2

+19 A:

If you have allow_url_fopen set to true:

$url = 'http://example.com/image.php';
$img = '/my/folder/flower.gif'
file_put_contents($img, file_get_contents($url));

Else use cURL:

$ch = curl_init('http://example.com/image.php');
$fp = fopen('/my/folder/flower.gif', 'wb');
curl_setopt($ch, CURLOPT_FILE, $fp);
curl_setopt($ch, CURLOPT_HEADER, 0);
curl_exec($ch);
curl_close($ch);
fclose($fp);

vartec 2009-04-07 07:15:24

Thanks bro, your code help me to solve the problem. But could u pls help me to make the script automated .I mean when a new gif image come to the url (“http://example.com/image.php”) then our script automatically fetch the new image and store it to my directory?

riad 2009-04-07 08:26:55

And how do you know, that the new image "came"?

vartec 2009-04-07 08:37:42

I think riad means using a `$_GET` variable containing the URL of the image `http://example.com/fetch-image.php?url=http://blabla.com/flower.jpg`. In the case of this example, you could just call `$_GET['url']` in your PHP script, like so: `$ch = curl_init($_GET['url']);`.

Mathias Bynens 2009-11-29 13:04:58

Answer 3

+3 A:

Here you go, the example saves the remote image to image.jpg.

function save_image($inPath,$outPath)
{ //Download images from remote server
    $in=    fopen($inPath, "rb");
    $out=   fopen($outPath, "wb");
    while ($chunk = fread($in,8192))
    {
        fwrite($out, $chunk, 8192);
    }
    fclose($in);
    fclose($out);
}

save_image('http://www.someimagesite.com/img.jpg','image.jpg');

Sam152 2009-04-07 08:00:15

Answer 4

A:

Thank you very much for all. using these tips and some string functions in php, i created a module for downloading all images from a particular site. i tried a software "Extreme Picture Finder" but it is not able to download images from site using "coppermine photo gallery" and that software also costs $50 but my code is able to download images from those sites too.

Once again thanks :)

boysmakesh 2010-07-31 10:00:58

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save image from php url using php

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