Prolem with if function

Question

Hi, something seems to be wrong with the first line of this if function, seems alright to me though.

if ($count1 == sizeof($map) && $count2 == sizeof($map[0])){
echo ";";
}else{
echo ",";
}

This is the error I get (line 36 is the first line of the above line.)

Parse error: parse error in C:\wamp\www\game\mapArrayConvertor.php on line 36

EDIT: The OP notes in an answer below that the error was a missing semi-colon on line 35 and not the code included in the question.

Answer 1

There appears to be nothing wrong with the syntax of your code. If the behavior is not what you expect, please post more details regarding the value of the variables and the intended and actual behavior of the code.

Answer 2

I don't see anything wrong with the code you have posted, so chances are the error is on a previous line. Perhaps a missed semicolon? Mismatched braces or parentheses?

Answer 3

check the line 35, it could be that line is wrong.

Answer 4

Seems I missed a ";" on line 35, sorry guys.

Answer 5

You could try:

if (($count1 == sizeof($map)) && ($count2 == sizeof($map[0]))){
  //blabla
}

Answer 6

You already found the problem, but... if this is just turning an array into a comma separated list, you could use the implode command to do it for you.