I want to create a collection of classes that behave like math vectors, so that multiplying an object by a scalar multiplies each field by that ammount, etc. The thing is that I want the fields to have actual names, instead of being treated as an index.
My original idea to implement this was creating a base class Rn with the overloads and then create derived classes with the pretty names. Something like this:
#include <iostream>
#include <algorithm>
using namespace std;
template<int N, class X=double>
struct Base{
X xs[N];
Base(){};
Base(X *data){
copy(data, data+N, xs);
}
Base operator*= (double d){
for(int i=0; i<N; i++){
xs[i] *= d;
}
return *this;
}
Base operator* (double d){
Base answer = *this;
answer *= d;
return answer;
}
//also operators for +=, +, multiplication from left, maybe [] too
};
struct Derived : public Base<2>{
Derived(double a, double b){
foo() = a;
bar() = b;
}
double &foo(){ return xs[0]; }
double &bar(){ return xs[1]; }
};
int main()
{
//this is OK:
double data[2] = {0.0, 2.0};
Base<2> b(data);
b = b*17.0;
cout << b.xs[0] << endl;
//I can't do this:
Derived x(0.0, 2.0);
x = x*17.0;
cout << x.foo() << endl;
return 0;
}
I get a compiler error whenever I try to use of of the operators that requires copying. gcc gave me the following compiler error:
teste.cpp: In function ‘int main()’:
teste.cpp:52: error: no match for ‘operator=’ in ‘x = x.Derived::<anonymous>.Base<N, X>::operator* [with int N = 2, X = double](1.7e+1)’
teste.cpp:31: note: candidates are: Derived& Derived::operator=(const Derived&)
I think the problem is that the overloading functions deal with Base objects that can't be converted to Derived ones, so I can't use them in the derived class. However, I can't come up with a solution. Is there a way around this or should I use a totally different approach?
Bonus question: is there some way that I can use std::valarray to keep from having to type lots and lots of operator overloads?