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3778

answers:

8

Why doesn't Java support a copy constructor like in C++?

+1  A: 

Guess they figured you can just make a clone() method instead?

Ryan Nielson
+7  A: 

I think the answer to this is very interesting.

For one, I believe that in Java all objects are on the heap, and while you don't have pointers, you do have "References". References have copy symantics and java internally keeps track of reference counts so that it's garbage collector knows whats safe to get rid of.

Since you only access objects through copyable references, the actual number of times you need to copy an object is greatly reduced (for example, in C++ just passing an object to a function (by value) results in new objects being copy constructed, in Java only the reference to the object is passed). The designers probably figured that clone() would be enough for the remaining uses.

dicroce
I agree. The copy constructor really is addressing memory management issues in C++.
Downvoted because:* Java does not use copy semantics (for objects). Passing an object around does NOT clone or copy the object, nor does it modify reference counts - it just passes the reference.* Too much confusion between copy semantics, and the fact that a reference to that object is copied.
Arafangion
In C++ you should be passing those objects by pointer or by reference as well to minimize excess copying. This isn't an issue of memory management, it's just (small) syntactic differences in the languages when you do want to make a deep copy of an object.
Mike Kale
@Arafangion, Wasn't it part of his whole answer that java does not do so, but instead copy the reference? +1 by me, anyway
Johannes Schaub - litb
+2  A: 

This is just my opinion (I am sure there is a justifiable answer)

Copy constructors in C++ are primarily useful when you are sending or returning instances of classes by value, since that is when the copy constructor is transparently activated.

Since in Java everything is returned by reference, and the VM is geared towards dynamic allocation, there really wasn't a justification for the complexities of a copy constructor.

In addition, since everything is by reference, a developer would often have to provide their own implementation and decision on how to clone fields.

Uri
A: 

It kind of does. When shallow copies are okay you have clone() and when they aren't you have to implement a deep copy just like C++.

The only substantive difference is that it's a factory method rather than a constructor proper, but in terms of flexibility and testability that's probably a good thing.

Aaron Maenpaa
A: 

I'm not much of a C++ programmer, but I do seem to remember a rule about the "three amigos" - copy constructor, assignment operator, and destructor. If you have one, then you likely need all three.

So maybe without a destructor in the language, they didn't want to include a copy constructor? Just a guess.

David Hodgson
Not quite. In C++, it's more like: If you need one of the three (say, a copy constructor), then you're very likely to need the other two as well, although you may not realize it at the time.
Dan Breslau
Also, if you don't need them, you should declare them as private and not implement them. This will keep the compiler from substituting it's own "shallow" copying version...
dicroce
+8  A: 

From Bruce Eckel:

Why does [a copy constructor] work in C++ and not Java?

The copy constructor is a fundamental part of C++, since it automatically makes a local copy of an object. Yet the example above proves that it does not work for Java. Why? In Java everything that we manipulate is a handle, while in C++ you can have handle-like entities and you can also pass around the objects directly. That’s what the C++ copy constructor is for: when you want to take an object and pass it in by value, thus duplicating the object. So it works fine in C++, but you should keep in mind that this scheme fails in Java, so don’t use it.

(I recommend reading the entire page -- actually, start here instead.)

Dan Breslau
+40  A: 

Java does. They're just not called implicitly like they are in C++ and I suspect that's your real question.

Firstly, a copy constructor is nothing more than:

public class Blah {
  private int foo;

  public Blah() { } // public no-args constructor
  public Blah(Blah b) { foo = b.foo; }  // copy constructor
}

Now C++ will implicitly call the copy constructor with a statement like this:

Blah b2 = b1;

Cloning/copying in that instance simply makes no sense in Java because all b1 and b2 are references and not value objects like they are in C++. In C++ that statement makes a copy of the object's state. In Java it simply copies the reference. The object's state is not copied so implicitly calling the copy constructor makes no sense.

And that's all there is to it really.

cletus
+1. While the rest of us were navel-gazing about object hierarchies, you cut straight to the syntax -- and probably answered the OP's *real* question while you did so.
Dan Breslau
That's an excellent explanation. Thanks so much!
Cuga
You might want to edit the assignment; you're assigning b2 to itself. Also "statemen tlike" has a space in the wrong place.
Carl Manaster
You could probably say "java *can*" if you define it, in this case.
rogerdpack