C++ long to string

Question

Yes, it is for homework....

Anyway - how to convert long into string?

THANK YOU! ^^

Answer 1

Check out std::stringstream.

Answer 2

You could use stringstream.

#include <sstream>

// ...
std::string number;
std::stringstream strstream;
strstream << 1L;
strstream >> number;

There is usually some proprietary C functions in the standard library for your compiler that does it too. I prefer the more "portable" variants though.

The C way to do it would be with sprintf, but that is not very secure. In some libraries there is new versions like sprintf_s which protects against buffer overruns.

Answer 3

   #include <sstream>


   ....

    std::stringstream ss;
    ss << a_long_int;  // or any other type
    std::string result=ss.str();   // use .str() to get a string back

Answer 4

The way I typically do it is with sprintf. So for a long you could do the following assuming that you are on a 32 bit architecture:

char buf[5] = {0}; // one extra byte for null

sprintf(buf, "%l", var_for_long);

Answer 5

int main()
{
    long mylong = 123456789;
    string mystring;
    stringstream mystream;
    mystream << mylong;
    mystring = mystream.str();
    cout << mystring << "\n";
    return 0;
}

Answer 6

There are several ways. Read The String Formatters of Manor Farm for an in-depth comparison.

Answer 7

Well if you are fan of copy-paste, here it is:

#include <sstream>

template <class T>
inline std::string to_string (const T& t)
{
    std::stringstream ss;
    ss << t;
    return ss.str();
}

Answer 8

I don't know what kind of homework this is, but most probably the teacher doesn't want an answer where you just call a "magical" existing function (even though that's the recommended way to do it), but he wants to see if you can implement this by your own.

Back in the days, my teacher used to say something like "I want to see if you can program by yourself, not if you can find it in the system." Well, how wrong he was ;) ..

Anyway, if your teacher is the same, here is the hard way to do it..

std::string LongToString(long value)
{
  std::string output;
  std::string sign;

  if(value < 0)
  {
    sign + "-";
    value = -value;
  }

  while(output.empty() || (value > 0))
  {
    output.push_front(value % 10 + '0')
    value /= 10;
  }

  return sign + output;
}

You could argue that using std::string is not "the hard way", but I guess what counts in the actual agorithm.

Answer 9

boost::lexical_cast<std::string>(my_long) more here http://www.boost.org/doc/libs/1_39_0/libs/conversion/lexical_cast.htm

Answer 10

One of the things not covered by anybody so far, to help you think about the problem further, is what format should a long take when it is cast to a string.

Just have a look at a spreedsheet program (like Calc/Excel). Do you want it rounded to the nearest million, with brackets if it's negative, always to show the sign.... Is the number realy a representation of something else, should you show it in Oractal or Hex instead?

The answers so far have given you some default output, but perhaps not the right ones.