I am having trouble figuring out mem_fun_ref. I have to admit, I usually use functors for this kind of thing, since they can be inlined for speed and profit. However, this code is not going to be a bottleneck and so I wanted to try this thing.
Here is an example of what I want to do. I know there are other ways to do it. I don't want to use copy, I don't want to use range member functions, I don't want to use a back_inserter. I specifically want to use mem_fun_ref. This is just a simple example, the real case is much more complicated. That said, I really don't know why this is wrong, but I am not familiar with mem_fun_ref or mem_fun.
Here's what I want to work:
#include <list>
#include <vector>
#include <algorithm>
#include <functional>
using namespace std;
int main()
{
    list<int> a;
    a.push_back(1);
    a.push_back(2);
    a.push_back(3);
    vector<int> b;
    // should work like magic!
    for_each(a.begin(), a.end(), bind1st(mem_fun_ref(&vector<int>::push_back), b));
}
But I get 3 errors:
1>c:\program files\microsoft visual studio 9.0\vc\include\functional(276) : error C2529: '_Right' : reference to reference is illegal
1>c:\program files\microsoft visual studio 9.0\vc\include\functional(281) : error C2529: '_Right' : reference to reference is illegal
1>c:\program files\microsoft visual studio 9.0\vc\include\functional(282) : error C2535: 'void std::binder1st<_Fn2>::operator ()(const int &(&)) const' : member function already defined or declared
1>        with
1>        [
1>            _Fn2=std::mem_fun1_ref_t<void,std::vector<int>,const int &>
1>        ]
1>        c:\program files\microsoft visual studio 9.0\vc\include\functional(276) : see declaration of 'std::binder1st<_Fn2>::operator ()'
1>        with
1>        [
1>            _Fn2=std::mem_fun1_ref_t<void,std::vector<int>,const int &>
1>        ]
reference to reference is illegal makes me think that the function needs to take a parameter by value. But of course, this is not possible to change in vector, and it's not possible to change it in my code either. Is there a simple change to get this to work? I need a solution that's a 1-liner.