C++ function pointer (class member) to non-static member function

Question

class Foo {
public:
    Foo() { do_something = &Foo::func_x; }

    int (Foo::*do_something)(int);   // function pointer to class member function

    void setFunc(bool e) { do_something = e ? &Foo::func_x : &Foo::func_y; }

private:
    int func_x(int m) { return m *= 5; }
    int func_y(int n) { return n *= 6; }
};

int
main()
{
    Foo f;
    f.setFunc(false);
    return (f.*do_something)(5);  // <- Not ok. Compile error.
}

How can I get this to work?

Answer 1

Try (f.*do_something)(5);

Answer 2

 class A{
    public:
        typedef int (A::*method)();

        method p;
        A(){
            p = foo;
            (this->*p)(); // <- trick 1, inner call
        }

        int foo(){
            printf("foo\n");
            return 0;
        }
    };

    void main()
    {
        A a;
        (a.*a.p)(); // <- trick 2, outer call
    }

Answer 3

The line you want is

   return (f.*f.do_something)(5);

(That compiles -- I've tried it)

"*f.do_something" refers to the pointer itself --- "f" tells us where to get the do_something value from. But we still need to give an object that will be the this pointer when we call the function. That's why we need the "f." prefix.

Answer 4

I think calling a non static member of the class could also be done using a static member function.