Currently I have a frustrating problem with forward declaration and template function. I have been trying to googling and do some modification but nothing has worked so far. Below is the snippet of the code: class TaskScheduler; --> //forward declaration of ‘struct TaskScheduler’ // // class TaskEvent { // // }; class HostTask { // //...
I have a class in C++/CLI that I'd like to give a property. I want to declare the property in a header file and then implement that property in a .cpp file. Here's the header: public ref class Dude { static property Dude^ instance { Dude^ get(); } } If I declare the header file and don't put anything in the c...
I can forward declare a function in a namespace by doing this: void myNamespace::doThing(); which is equivalent to: namespace myNamespace { void doThing(); } To forward declare a class in a namespace: namespace myNamespace { class myClass; } Is there a shorter way to do this? I was thinking something along the lines of: cl...
Hi everyone! I'm having some problems with my class because they both depends on each other, to one can't be declared without the other one being declared. class block: GtkEventBox { public: block(board board,guint x,guint y): image("block.png") { this.board = board; this.x = x; this.y =...
I am curious about the impact my typedef approach has on my builds. Please consider the following example. #include "SomeClass.h" class Foo { typedef SomeClass SomeOtherName; SomeOtherName* storedPointer; void setStoredPointer(SomeOtherName* s); } void Foo::setStoredPointer(SomeOtherName* s) { storedPointer = s; } ...
Is following code legal C++ or not? class Foo { class Bar; void HaveADrink(Bar &bar); void PayForDrinks(Bar &bar); public: void VisitABar(int drinks); }; class Foo::Bar { public: int countDrinks; }; void Foo::HaveADrink(Bar &bar) { bar.countDrinks++; } void Foo::PayForDrinks(Bar &bar) { bar.countDrinks = 0; } void ...
I want to sort a list using my own cmp function. For the purpose of this discussion we can use the following example which is equivalent to what I'm trying to do: print "\n".join([str(bla) for bla in sorted(mylist, cmp = cmp_configs)]) However, because of the way I organized my code, I much prefer to put the definition of cmp_configs...
What's the proper way to inherit from a template class with the template argument being a nested class within the inheriting class? class SomeClass : public TemplateClass<NestedClass> { class NestedClass {}; }; ...
Is it possible to forward declare a class that uses default arguments without specifying or knowing those arguments? For example, I would like to declare a boost::ptr_list< TYPE > in a Traits class without dragging the entire Boost library into every file that includes the traits. I would like to declare namespace boost { template<class...
So I have a class A, where I want to call some class B functions. So I include "b.h". But, in class B, I want to call a class A function. If I include "a.h", it ends up in an infinite loop, right? What can I do about it? ...
The follwing code is compiled in VC++6. I don't understand why I am getting the compilation error "C2079: 'b' uses undefined class 'B'" for the following code? //Class B Source #include "B.h" void B::SomeFunction() { } //Class B Header #include "A.h" struct A; class B { public: A a; void SomeFunction(); }; /...
I would like to check the type of a superclass A against the type of a subclass B (with a method inside the superclass A, so that B will inherit it). Here's what I thought did the trick (that is, the use of forward declaration): #include <iostream> #include <typeinfo> using namespace std; class B; class A { public: int i_; ...
I have some trouble forward declaring a function that uses boost::enable_if: the following piece of code gives me a compiler error: // Declaration template <typename T> void foo(T t); // Definition template <typename T> typename boost::enable_if<boost::is_same<T, int> >::type foo(T t) { } int main() { foo(12); return 0; } Wh...
I am new to Javascript and got confused by how the function declaration works. I made some test on that and got some interesting results: say(); function say() { alert("say"); } The forward-declaration worked and popup "say" On the opposite say(); say = function() { alert("say"); } did not work, although it also declared...
Is there a tool that would go through a list of files and would spit out a header file with forward declarations of classes it encounters? Ideally, I would like to integrate it into Visual C++'s build process. ...
I'm trying to use forward declarations and d-pointers to eliminate some include dependencies. Everything is working well, except that I have used XList typedefs for readability in many places (e.g: typedef QList<X> XList). The workaround for the typedef forward declaration issue is to use inheritance: class XList : public QList<X>{};. ...
I know that I can forward declare a class as follows: class Foo; // ... now I can use Foo* However, can I do something like this: class Bar { public: virtual void someFunc(); }; // ... somehow forward declare Class Foo as : public Bar here someFunc(Foo* foo) { foo -> someFunc(); } class Foo: public Bar { } ? Thanks! ...
I know that I can do: class Foo; but can I forward declare a class as inheriting form another, like: class Bar {}; class Foo: public Bar; ? Thanks! ...
In the followint code, how does the pointer conversion & multi-inheritance play together? class Foo { public: virtual void someFunc(); }; class Bar; void someWork(Bar *bar) { ((Foo*) bar)->someFunc(); } class Bar: public Zed, public Foo { ... virtual void someFunc() { ... do something else ... } } Bar bar; int main() { som...
I have two classes and both of them uses some of the other class, on example: // class1.h class Class1; #include "class2.h" class Class1 { public: static Class2 *C2; ... }; // class2.h class Class2; #include "class1.h" class Class2 { public: static Class1 *C1; ... }; And when I define it like in example above, it works ...