memmove implementation in C
Hi, Can some one help me to understand how memmove is implemented in C. I have only one special condition right ? if((src<dst)&&((src+sz) > dst)) copy from the back Also does it depend on the way stack grows ? ...
memmove
How does the memory overlap occur and how is it controlled?
While reading about memmove I read that it can handle *MEMORY OVERLAPS*but I am unable to get how a memmory overlap can occur between two strings and how can this function still copy the block of memory correctly. ...
What are real significant cases when memcpy() is faster than memmove()?
The key difference between memcpy() and memmove() is that memmove() will work fine when source and destination overlap. When buffers surely don't overlap memcpy() is preferable since it's potentially faster. What bothers me is this potentially. Is it a microoptimization or are there real significant examples when memcpy() is faster so t...
Fast memmove for x86 and +1 shift (for Move-to-front transform)
Hi For fast MTF ( http://en.wikipedia.org/wiki/Move-to-front_transform ) i need faster version of moving a char from inside the array into the front of it: char mtfSymbol[256], front; char i; for(;;) { \\ a very big loop ... i=get_i(); \\ i is in 0..256 but more likely to be smaller. front=mtfSymbol[i]; memmove(mtfS...
Can I call memcpy() and memmove() with "number of bytes" set to zero?
Do I need to treat cases when I actully have nothing to move/copy with memmove()/memcpy() as edge cases int numberOfBytes = ... if( numberOfBytes != 0 ) { memmove( dest, source, numberOfBytes ); } or should I just call the function without checking int numberOfBytes = ... memmove( dest, source, numberOfBytes ); Is the check in ...
Strange behavior of memcpy/memmove
Hi everybody, I have the problem that memcpy/memmove change the pointer of a struct FOO foo, which is neither src nor destination of the function. Here are the gdb outputs: Before memmove(y,y_temp,size_y);: (gdb) p y $38 = 0xbff7a2e0 (gdb) p y_temp $39 = (float *) 0x815ea20 (gdb) p foo $40 = (FOO *) 0x81d4e90 and after: (gdb) p y_t...