I am trying to learn mysql and having some problem with updating/adding data to the table
this is my code and after running this page when I go to phpmyadmin to see if the new data showed up, i dont see it there.
<?php
$conn = mysql_connect($dbhost, $dbuser, $dbpass);
if(!$conn) { die("Could not connect"); }
$dbname = "test";
mys...
This is one of the more confusing functions I've attempted. The logic works within a select statement, but I can't seem to create a user-defined function.
Here's the error:
"You have an error in your SQL syntax;
check the manual that corresponds to
your MySQL server version for the
right syntax to use near 'delimiter$$
creat...
INSERT INTO `tims`.`pending_profile`(`id`, `nickname`, `location`, `role`, `yog`, `interests`, `favMoment`, `gainThisYr`, `futurePlans`, `bio`)
VALUES ('1', '1', '1', '1', '', '1', '1', '1', '1', '1')
ON DUPLICATE KEY UPDATE ( nickname ='1', location= '1', role= '1',yog= '1',interests= '1',favMoment= '1',gainThisYr= '1',futurePlans= '1'...
I'm running the following line :
mysql_query("INSERT INTO tags
SET tag = '".$onesearch."',
SET date = '".date('d-m-Y')."'") or die(mysql_error());
...and its dieing saying this:
You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right synt...
I'm running a query to update a small group of 'items' in a table, from PHP.
Running the code with "Sequel Pro" executes it perfectly, while running it on PHP using mysql("query here"); fails miserably.
Is there anything wrong with my query?
UPDATE `service_joblocation`
SET `in_use` = '1',
`in_use_since` = '1283488686',...
How should i use while loop in mysql?
while exists (select * from table1)
Do
//sql statements
end while
Error Code : 1064
You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near while....
This what I want to do:
Inserting 20K records into a table...
This part of my code creates a multiple query by this:
$sql = "";
$sql .= "INSERT INTO projects
(project_id, project_name, project_description, project_deadline, project_status, project_priority)
VALUES ('" . $project_id . "', '" . $name . "', '" . $description . "', '" . $final_deadline . "', '" . $status . "', '" . $p...
Hi,
I have recently started learning SQL, I can't determine what is causing my syntax error (see below):
CREATE TABLE Users(
user_id smallint not null auto_increment,
username varchar(50) unique,
password varchar(41),
dob date,
session_id varchar not null,
cookie varchar not null,
PRIMARY KEY(user_id),
C...
I created this using MySQL WorkBench
CREATE TABLE IF NOT EXISTS `bakasura_new`.`cities` (
`id` INT(11) UNSIGNED NOT NULL AUTO_INCREMENT ,
`name` VARCHAR(255) NOT NULL COMMENT 'City Name' ,
`short_name` VARCHAR(255) NOT NULL COMMENT 'Short Name' ,
`country_id` INT(11) UNSIGNED NOT NULL ,
PRIMARY KEY (`id`) ,
INDEX `fk_cities...
I'm importing a stored procedure which I just exported from my development server into my production one and I ran into the following error in phymyadmin.
SQL query: Documentation
$$ CREATE DEFINER = `devuser`@`localhost` FUNCTION `get_refundable_amount` (
enrol_id INT
) RETURNS double( 10, 2 ) READS SQL DATA BEGIN DECLARE refundable_a...
Any idea why the following query syntax is wrong:
SELECT year, sum(profit)
FROM BASEDATA b
group by year WITH rollup
Error Code: 1064
You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near.....
MYSQL Version 5.0.77-community-log
...
I tried this example via phpMyAdmin
http://www.databasejournal.com/features/mysql/article.php/3569846/MySQL-Stored-Functions.htm
mysql> DELIMITER |
mysql>
CREATE FUNCTION WEIGHTED_AVERAGE (n1 INT, n2 INT, n3 INT, n4 INT)
RETURNS INT
DETERMINISTIC
BEGIN
DECLARE avg INT;
SET avg = (n1+n2+n3*2+n4*4)/8;
RETURN avg;
...
INSERT into error_log
(id_user, id_error, severity, date)
VALUES
('93, '1', '6', '1285886665')
Throwing
You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '1', '6', '1285886794')' at line 4
Table
CREATE TABLE `error_log` (
`id` int(25) N...
I'm trying to understand why the following is failing and I'm not able to see it. The phpMyAdmin on our development server generated this exactly, but when I try importing it - I'm running into a weird parsing(?) error.
mysql> DELIMITER $$
mysql>
mysql> --
mysql> -- Functions
mysql> --
mysql> DROP FUNCTION IF EXISTS `get_class_nextsessi...
It's 12:30am and I have been coding for 9 hours straight. I really need to get this project done, but MySQL is messing with my deadline. Could you examine this snippet for me and see if you can find out what is wrong?
PHP/MySQL Query
$q = $this->db->query("SELECT * FROM bans WHERE ip='".$ip."'");
Keeps returning the following error.....
Hi there,
I'm receiving the following error with this page while trying to retrieve information from my database;
You have an error in your SQL syntax;
check the manual that corresponds to
your MySQL server version for the
right syntax to use near 'FROM
catalog_product_entity cpe inner join
catalog_product_entity_varchar c...
The sql i wrote
**delimiter |
CREATE
DEFINER=CURRENT_USER
TRIGGER set_profiletype_after_insert BEFORE INSERT ON trl_translator FOR EACH ROW
BEGIN
UPDATE trl_profile SET trl_profile.type = 'translator' WHERE trl_profile.profile_id = NEW.translator_id
END
|
delimiter ;**
The error given
[SQL]
**CREATE
DEFINER=CURRENT_USER
TRIGG...
I get the following error below and was wondering how can I fix it?
You have an error in your SQL syntax; check the manual that corresponds to
your MySQL server version for the right syntax to use near '.user_id WHERE
users.active IS NULL AND users.deletion = 0) WHERE users.active' at line 4
And here is my MySQL code (line breaks inse...
Trying to enter a value into a mediumblob field in a mySQL table but I'm getting:
1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'WHERE id = 40' at line 3
INSERT INTO 'Picture'
VALUES (efvr)
WHERE id = 40
What's wrong with this statem...
See something wrong in my code? I can't get the update function to work.. weird thing is the rest works correctly, and the same code works 100% on another page.
<?php
include("config.php");
$id = $_GET['id'];
$number = $_GET['no'];
$result = mysql_query("SELECT * FROM comments WHERE commentid = '$id'")
or die(mysql_error());
$row ...