I have two pointers to the same C string. If I increment the second pointer by one, and assign the value of the second pointer to that of the first, I expect the first character of the first string to be changed. For example: #include "stdio.h" int main() { char* original_str = "ABC"; // Get pointer to "ABC" char* off_by_o...
Lets assume I am a game and I have a global int* that contains my health. A game trainer's job is to modify this value to whatever in order to achieve god mode. I've looked up tutorials on game trainers to understand how they work, and the general idea is to use a memory scanner to try and find the address of a certain value. Then modify...
I read about Endianness and understood squat... so I wrote this main() { int k = 0xA5B9BF9F; BYTE *b = (BYTE*)&k; //value at *b is 9f b++; //value at *b is BF b++; //value at *b is B9 b++; //value at *b is A5 } k was equal to A5 B9 BF 9F and (byte)pointer "walk" o/p was 9F BF b9 A5 so I get it byte...
Hello! Trying to understand why this doesn't work. I keep getting the following errors: left of '->nextNode' must point to class/struct/union/generic type (Also all the lines with a -> in the function new_math_struct) Header file #ifndef MSTRUCT_H #define MSTRUCT_H #define PLUS 0 #define MINUS 1 #define DIVIDE 2 #defi...
Having very similiar code like so: LINT_rep::Iterator::difference_type LINT_rep::Iterator::operator+(const Iterator& right)const { return (this + &right);//IN THIS PLACE I'M GETTING AN ERROR } LINT_rep::Iterator::difference_type LINT_rep::Iterator::operator-(const Iterator& right)const {//substracts one iterator from another re...
I am a brand new programming student, so please forgive my ignorance. My assignment states: Write a program that declares an array of 10 integers. Write a loop that accepts 10 values from the keyboard and write another loop that displays the 10 values. Do not use any subscripts within the two loops; use pointers only. Here is my code: ...
Wouldn't it make sense if p->m was just syntactic sugar for (*p).m? Essentially, every operator-> that I have ever written could have been implemented as follows: Foo::Foo* operator->() { return &**this; } Is there any case where I would want p->m to mean something else than (*p).m? ...
Hello, In a C struct I have defined a function pointer as follows: typedef struct _sequence_t { const int seq[3]; typedef void (* callbackPtr)(); } sequence_t; I want to initialize a var of that type globally with: sequence_t sequences[] = { { { 0, 1, 2 }, toggleArmament }, }; And I keep getting error telling me that there a...
I'm getting said error on this line "b = true". Now Why am I getting this error? Aren't I pointing to TurnMeOn and thus saying TurnMeOn = true? class B{ void turnOn(bool *b){b = true} }; int main(){ B *b = new B(); bool turnMeOn = false; b->turnOn(&turnMeOn); cout << "b = " << turnMeOn << endl; } ...
Hi simple question in c++ , say i have a loop and i have function that returns pointer to item so i have to define inner loop pointer so my question is what to do with the pointer inside the loop , delete it ? or to set it with new value is good for example: for(int i =0;i<count();i++) { ptrTmp* ptr = getItemPtr(); // do somthi...
In brief, my question is about member variables as pointers in unmanaged C++. In java or c#, we have "advanced pointer". In fact, we can't aware the "pointer" in them. We usually initialize the member of a class like this: member = new Member(); or member = null; But in c++, it becomes more confusing. I have seen many styles: usin...
is that correct to write a constructor like this? class A { A::A(const A& a) { .... } }; if yes, then is it correct to invoke it like this: A* other; ... A* instance = new A(*(other)); if not, what do you suggest? Thanks ...
Suppose I have the following C++ class: class Foo { double bar(double sth); }; double Foo::bar(double sth) { double a,b,c,d,e,f a = b = c = d = e = f = 0; /* do stuff with a..f and sth */ } The function bar() will be called millions of times in a loop. Obviously, each time it's called, the variables a..f have to be allocated....
I was playing around with C, anyways I was thinking how can file pointer (which points to a struct type), be tested if NULL as for instant: FILE *cfPtr; if ( ( cfPtr = fopen( "file.dat", "w" ) ) == NULL ) I tried to do that myself, but an error occurs. struct foo{ int x; }; struct foo bar = {0}; if (bar == NULL) puts("Yay\n...
Hi, When I read one char* from std::cin and I want to write it to std::cout, it prints until it finds a \0 in memory. So what did was: char c; cin >> c; char* pChar = &c; pChar++; *pChar = '\0'; println(&c); // My own method: void println(char * str) { cout << str << endl; } But I don't think this is a safe action. Is there a safer ...
I'm trying to allocate memory for a multidimensional array (8 rows, 3 columns). Here's the code for the allocation (I'm sure the error is clear for you) char **ptr = (char **) malloc( sizeof(char) * 8); for (i = 0; i < 3; i++) ptr[i] = (char *) malloc( sizeof(char) * 3); The crash happens when I reference this: ptr[3][0]; ...
I know it's simple, but I can't seem to make this work. My function is like so: int GefMain(int array[][5]) { //do stuff return 1; } In my main: int GefMain(int array[][5]); int main(void) { int array[1800][5]; GefMain(array); return 0; } I referred to this helpful resource, but I am still ...
I know I can pass a function pointer as a template parameter and get a call to it inlined but I wondered if any compilers these days can inline an 'obvious' inline-able function like: inline static void Print() { std::cout << "Hello\n"; } .... void (*func)() = Print; func(); Under Visual Studio 2008 its clever enough to get it dow...
1- How does this work: char *ptr = "hi"; Now the compiler will put this string in the memory (I'm guessing the stack), and create a pointer to it? Is this is how it works? 2- Also if it is created locally in a function, when the function returns will the memory occupied by the string be freed? 3- Last but not least, why is this not ...
I have a method in a class trying to return a pointer: <?php public function prepare( $query ) { // bla bla bla return &$this->statement; } ?> But it produces the following error: Parse error: syntax error, unexpected '&' in /home/realst34/public_html/s98_fw/classes/sql.php on line 246 This code, however, works: <?php ...