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understanding xslt handling of elements with attributes

Answer 1

+2 A:

You can express a conditional match on an element based on an attribute value with, for example

element[@attribute = 'hello']

For your specific case:

<p class="deck">Text here</p>

Try:

//p[@class = 'deck']/text()

Which is an XPath expression and can be read as returning a sequence of the text content of all p elements with an attribute class whose value is 'deck'.

XSLT uses XPath to navigate XML documents, so it might be worth reading up on XPath as well as XSLT.

Brabster 2009-08-18 20:31:22

I'm reading up w3schools right now, but am having difficulty understanding the language and concepts. their "try it" section is allowing me to gain understanding though, by making changes and seeing what the change does. I'm reading up on XPath as well.

stephenbayer 2009-08-18 21:06:23

Answer 2

+1 A:

I don't see an anywhwhere to serve as the base of your template. I'm assuming this is a cut and paste problem, though.

Anyway, an xpath to find all p elements with class attribute set to deck is: //p[@class='deck']

You could iterate through them with:

<xsl:for-each select="//p[@class='deck'">
</xsl:for-each>

jsight 2009-08-18 20:32:01

thank you very much, the final code ended up being: <Description> <xsl:for-each select="//p[@class='deck']" > <xsl:copy > <xsl:apply-templates/> </xsl:copy> </xsl:for-each> </Description>

stephenbayer 2009-08-18 20:44:44

Answer 3

+1 A:

Hmm... Something like this perhaps:

<Description>
    <xsl:choose>
        <xsl:when test="//p[@class='deck']">
            <xsl:value-of select="//p[@class='deck']" />
        </xsl:when>
        <xsl:otherwise>
            <xsl:test> </xsl:text>
        </xsl:otherwise>
    </xsl:choose>
</Description>

LorenVS 2009-08-18 20:33:55

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