I'm trying to obtain a list of information for the root element of an xml document using a transformation. The pieces I can't figure out are:
How do I obtain the default namespace url?
How can I obtain a list of every xmlns prefix and its related url?
Here's my xml file:
<?xml version="1.0" encoding="UTF-8"?>
<?xml-stylesheet type="text/xsl" href="/example.xsl"?>
<foo:mytag xmlns="http://default.example.com/"
xmlns:foo="http://foo.example.com/"
xmlns:bar="http://bar.example.com">
</foo:mytag>
And here is my xsl file:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output
doctype-public="-//W3C//DTD XHTML 1.1//EN"
doctype-system="http://www.w3.org/TR/xhtml11/DTD/xhtml11.dtd"
encoding="UTF-8"
indent="yes"
method="xml"
omit-xml-declaration="no"
version="1.0" />
<xsl:template match="/">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<title></title>
</head>
<body>
default namespace - <b>???</b><br />
full tag name - <b><xsl:value-of select="name(*)"/></b><br />
xmlns for tag - <b><xsl:value-of select="namespace-uri(*)"/></b><br />
tag prefix - <b>???</b><br />
tag name - <b><xsl:value-of select="local-name(*)"/></b><br />
List of xmlns - <br />
????
</body>
</html>
</xsl:template>
This transformation is being done in the browser. Basically what I'm expecting as a result:
default namespace - http://default.example.com/
full tag name - foo:mytag
xmlns for tag - http://foo.example.com/
tag prefix - foo
tag name - mytag
List of xmlns -
- http://default.example.com/
foo - http://foo.example.com/
bar - http://bar.example.com/
Am I missing something obvious to fill in the missing data?