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Answer 1

A:

The method for evaluating your Xpath is not correct for firefox.

See https://developer.mozilla.org/en/Introduction_to_using_XPath_in_JavaScript For a good intro to using XPath in firefox.

Also see http://www.w3.org/TR/xpath for XPath details

For your example, you would need

var node = xmlDoc.evaluate("/bookstore/appSettings/add[@key='myKey']", xmlDoc, null,XPathResult.FIRST_ORDERED_NODE_TYPE,null).singleNodeValue;

See http://www.w3schools.com/XPath/xpath_examples.asp for How to accomplish this in both IE and firefox

Jonathan Fingland 2009-10-20 13:46:00

@Reubens, quite right. Corrected.

Jonathan Fingland 2009-10-20 13:51:24

where do you need xmlDoc.evaluate?

Rubens Farias 2009-10-20 13:52:45

*document*.evaluate() is for DOM3 XPath supporting browsers

Jonathan Fingland 2009-10-20 13:54:36

Answer 2

+1 A:

I would strongly advise using a library such as jQuery to make your life easier - no more document.getElementById()-ing! In jQuery you can just do:

$.ajax({
    type: 'GET',
    url: 'test.xml',
    dataType: 'xml',
    success: processXml
});

function processXml(xml)
{
    xml = $(xml);
    var value = xml.find('bookstore appSettings add[key=myKey]').attr('value');
    alert(value);
}

Edit: I'm not that familiar with XPath, so I figured I would explain the find() call in case I misread what you're trying to select from the XML. jQuery uses CSS selector syntax. So, that find() will select add nodes that have the key attribute equal to myKey, which are descendant elements of appSettings, which descend from bookstore elements.

Matt Ball 2009-10-20 13:48:15

Thanks everyone for the help... Matt, any ideas why it's not working on IE6?

rod 2009-10-20 14:00:29

Nevermind, I think it's getting blocked by my browser security, thanks again for the help.

rod 2009-10-20 14:01:54

I still suggest you try out jQuery - it removes all the nasty browser dependency (for the most part) like having to do object detection for the XMLHttpRequest.

Matt Ball 2009-10-20 14:03:22

Answer 3

A:

Just to make sure your XML is returning correctly, can you please alter your code:

// ...
xhttp.send("");
xmlDoc=xhttp.responseXML;

alert(xmlDoc.xml)

I suspect you don't get your XML data back from your request.

Rubens Farias 2009-10-20 14:05:07

Answer 4

A:

Before dealing with JavaScript, I would try to open the XML document directly in the browser typing the URL and see if it displays correctly.

antispam 2009-10-21 08:10:37

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Error parsing XML file in JavaScript

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