I don't really understand the difference between the XPath functions name and local-name.
Could you give an example of a situation where they would differ?
Given this example:
<?xml version="1.0" ?>
<html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en" lang="en">
<head></head>
</html>
I get the same result with these two queries: //*[local-name()="head"] and //*[name()="head"]. Why is that?
With the XML being
<x:html xmlns:x="http://www.w3.org/1999/xhtml"/>
the stylesheet
<xsl:stylesheet
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
version="1.0">
<xsl:output indent="yes"/>
<xsl:template match="*">
<local-name><xsl:value-of select="local-name()"/></local-name>
<name><xsl:value-of select="name()"/></name>
</xsl:template>
</xsl:stylesheet>
outputs
<local-name>html</local-name>
<name>x:html</name>
So the local-name() result is without any prefix, the name() result might include a prefix. In your sample with a default namespace declaration no prefix is present, therefore name() and local-name() give the same result.