How to check in which position (landscape or portrait) os the iPhone now?

Question

I have an app with a tab bar, and nav controllers in each tab. When user shakes the device, a UIImageView appears as a child view in the nav controller. But the UIImageView must contain a special image, depending on the device's current orientation.

If I write just

- (void)willAnimateRotationToInterfaceOrientation:(UIInterfaceOrientation)
if (interfaceOrientation == UIInterfaceOrientationPortrait|| interfaceOrientation == UIInterfaceOrientationPortraitUpsideDown) { 
//Code
}
else if (interfaceOrientation == UIInterfaceOrientationLandscapeRight||interfaceOrientation == UIInterfaceOrientationLandscapeLeft) {
//Code
}
}

The view just goes crazy if user rotated the device before shaking. Is there a method to get iPhones current orientation?

Answer 1

Use the [[UIDevice currentDevice] orientation] method, as specified here.

Answer 2

To addon to the already answered question:

You use [[UIDevice currentDevice] orientation] which will yield one of these values:

typedef enum {
   UIDeviceOrientationUnknown,
   UIDeviceOrientationPortrait,
   UIDeviceOrientationPortraitUpsideDown,
   UIDeviceOrientationLandscapeLeft,
   UIDeviceOrientationLandscapeRight,
   UIDeviceOrientationFaceUp,
   UIDeviceOrientationFaceDown
} UIDeviceOrientation;

The documentation can be found here - (orientation) and here - (UIDeviceOrientation).

(I don't mean to claim the former anwser, but this information was to big for a comment.)