how print all the attributes values of the title attributes in all my xml files

Question

I wonder if anybode knows what command or bash-script-code I can use to print out all the values of the title attributes in all my xml files (in current directory).

I'm using cygwin and have file names containing white spaces.

( I've been googling around and there are a lot of suggestions on downloading other utilities. If I can avoid that it would be good for me. For example I installed sgrep and then got this error: sh: m4: command not found system("m4 -s") returned non zero exit status (32512). Preprocessor returned empty file )

If there is an Xpath program that is free to download to windows and use like a stand alone search program, that would be great too =)

Thanks in advance for helping out / T

Answer 1

Do you have xml_grep installed? It is free and came standard on my install of centOS here. It can take an xpath expression and print the results.

Answer 2

If the tag and the title attribute are all on the same line, but there are line feeds between the different instances of your tag, the following could work for you. For example

<mytag someAttr="blah" Title="The Title goes here" ...

Then you could do something like the following in order to find the tags of interest that contain a Title attribute:

grep -ro '<mytag[ \t].*Title="[^"]*"' /path/to/directory/to/search

Alternatively, you should be able to use find and xargs:

find /your/search/path -iname '*.xml' -print0 | \
    xargs -0 -r grep -ro '<mytag[ \t].*Title="[^"]*"'

Now that you know you have the correct tag and its corresponding Title attribute, you just want the Title attribute, so you can use grep's -o option to output only the data matching the regular expression followed by cut to extract the value of the Title:

grep -ro '<mytag[ \t].*Title="\([^"]*\)"' /path/to/directory/to/search | \
    grep -o 'Title="[^"]*"' | cut -f2 -d'"'