extract filename from path in csh shell -- from list of files

Question

How to extract filename from the path; i have a list of files. I'm using csh shell, and have awk, sed, perl installed.

/dfgfd/dfgdfg/filename

should give me

filename

I tried basename:

    find $PROJDIR -name '*.c' -o -name '*.cc' -o -name '*.h'
 | xargs grep -l pattern | xargs basename

and it gave me the following error:

basename: too few arguments Try `basename --help' for more information.

thx

Answer 1

The standard program basename does what you want:

$ basename /dfgfd/dfgdfg/filename
filename

Answer 2

This kind of workaround worked for me. You said you had perl so this should run. It replaces all nonspace text up to the last / with nothing (effectively deleting it).

find $PROJDIR -name '*.c' -o -name '*.cc' -o -name '*.h'
 | xargs grep -l pattern | perl -pi -e "s/\S+\///g"

Answer 3

Ok I found a nice solution using AWK:

    find  $PROJECT_DIR  -name '*.c' -o -name '*.cc' -o -name '*.h' 
| xargs grep -l PATTERN | awk -F "/" '{print $NF}'