This uses bash arrays - but I see from the comments to another answer that the code isn't supposed to run under bash (despite the bash tag originally applied to the question); it is meant to run under the busybox shell.
I'm almost certain it doesn't answer the question because the question is substantially unanswerable given the limitations of busybox. In times past, I have used a custom program I called 'escape' to build up an argument string that can be eval'd to get the original arguments - spaces and all. But that requires support from outside the shell.
This solution only uses 'bash'. I'm not sure it is fully idiomatic bash code, but it works.
#!/bin/bash
i=0
Qflag=0
for arg in "$@"
do
if [ "X$arg" = "X-Q" ]
then Qflag=1
else args[$((i++))]=$arg
fi
done
if [ $Qflag = 1 ]
then exec acommand "${args[@]}" 2>&1 >/dev/null
else exec acommand "${args[@]}"
fi
The first loops builds up an array, args, with the arguments to the script, except it doesn't add '-Q' to the list and records its presence in variable Qflag.
The if statement at the end notes whether Qflag was set to 1, and if so, sends the errors from 'acommand' to standard output and sends regular standard output to /dev/null (which is different from the effect if the I/O redirections are reversed - that would send standard output to /dev/null and send standard error to the same place, forcing silence on 'acommand').
The use of 'exec' is a trivial optimization that simplifies exit status handling in this case.
Tested with 'acommand' that prints its arguments on separate lines:
#!/bin/sh
for arg in "$@"
do echo "$arg"
done
and with command lines such as:
bash wrapper.sh -c -d 'arg with spaces'
which produces the output:
-c
-d
arg with spaces
Obviously, with the I/O redirection in place, there is no output from:
bash wrapper.sh -c -Q -d 'arg with spaces'
However, if you omit the I/O redirection, you get to see the same output.