header("Content-type: image/gif");
readfile($filename);
The above can only be used to show gif images.
Is there a header that can be used to show jpg/png/gif?
views:
99answers:
3
+4
A:
header("Content-type: image/gif");
OR
header("Content-type: image/jpeg");
OR
header("Content-type: image/png");
jitter
2009-10-31 11:16:28
Do I have other options than list them all?
another
2009-10-31 11:17:25
**You can't use more than one.** It should match the content you're sending. If you're readfile'ing a GIF, it should be `image/gif`, a JPEG should be `image/jpeg`, and a PNG should be `image/png`.
ceejayoz
2009-10-31 11:23:37
Look <img src="" />,you dont have to specify its exact type.
another
2009-10-31 11:25:27
That's because servers send the right content type so the browser knows what to do with it.
ceejayoz
2009-10-31 11:26:04
@new - This is called a MIME Type. http://en.wikipedia.org/wiki/Internet_media_type
txyoji
2009-10-31 11:26:40
It's also used to server http request,can I leave the content type to servers like <img src="" />?
another
2009-10-31 11:28:40
The server will handle `<img>` tags because it's directly serving the image file. It won't handle a PHP script using `readfile()` because all the server knows is that it's a PHP script - it'll try to use `text/html` like all other PHP scripts. This is why you have to specify a `Content-type` header in such a script.
ceejayoz
2009-10-31 11:50:27
Then is there a way to let server directly serve the image file?
another
2009-10-31 11:55:21
Yes - link to it directly instead of using a PHP script. Otherwise, you'll need to use one of the (easy) MIME type detection techniques described in other answers.
ceejayoz
2009-10-31 13:56:18
+3
A:
You need to know or figure out what type of file it is, and send the proper type. There's no catch-all content type for images that'll work for GIF, PNG, and JPEG all at once.
finfo_file() will let you detect the type of an image (or any other file).
ceejayoz
2009-10-31 11:25:28
+4
A:
This should work for all image types:
$size = getimagesize($filename);
header('Content-type: ' . $size['mime']);
readfile($filename);
Alix Axel
2009-10-31 11:43:26