It sounds like you're running into assumptions made based on the previous implementation (Codewarrior). For example:
#include <iostream>
int main() {
std::cout << "string literal\n";
return 0;
}
This relies on iostream including something it's not required to declare: the operator<<(ostream&, char const*)
overload (it's a free function, not a method of ostream like the others). And to be completely unambiguous, #include <ostream>
is also required above. In C++, library headers are allowed to include any other library header, in general, so this problem crops up whenever someone inadvertently depends on this.
(That the extra header is required in this particular circumstance is considered a flaw by many, including me, and almost all implementations do provide the declaration of this function in iostream. It is still the shortest, common example I know of to illustrate this.)
It's often more subtle and complicated than this simple example, but the core issue is the same. The solution is to check every header to make sure it includes any libraries it requires, starting with the ones giving you the errors. E.g. #include <vector>
and make sure you use std::vector
(to avoid relying on it being in the global namespace, which is done in some, mostly old and obsolete now, implementations) when you get "vector does not name a type".
You might also be running into dependent types, in which case you'd add typename.