If I have a VB.Net function that returns an Int32, but uses an unsigned int (UInt32) for calculations, etc. How can I convert a variable "MyUintVar32" with a value of say "3392918397 into a standard Int32 in VB.Net?
In c# if I just do a "return (int)(MyUintVar32);", I get -902048899, not an error.
I've tried several different methods. What is the difference in the way c# handles these conversions versus VB.Net?
It's not an optimal solution, but you can use BitConverter to get a byte array from the uint and convert the byte array to int.
3392918397 is too big to fit into a signed 32-bit integer, that's why it is coming out negative, because the most significant bit of 3392918397 is set.
1100 1010 0011 1011 1101 0011 0111 1101
If you want to maintain integers of this proportion inside a signed integer type, you'll need to use the next size up, a 64-bit signed integer.
You can't convert 3392918397 into an Int32 since that number is too large to fit in 31 bits. Why not just change the function to return a UInt32?
Or after doing the Uint32 work check it against MAXINT and 0.
If > MAXINT and < 0 then you're ok. If not you "overflowed" and should throw an exception.
I don't remember if MAXINT is defined. You can use: 2^31 - 1 instead.