How to convert a Integer to a ByteString in Haskell

Question

Hi,

We'd like to serialize data in a specific binary format. We use Data.ByteStrings internally.

So, the question is: How to convert the different data types we use to a ByteString. For String we have no problem, we can use encodeLazyByteString UTF8 "string". But we'd also like to convert Integers to ByteStrings (big-endian).

Does anyone know how to do that and/or has any good tips using Haskell and binary formats?

Thanks!

Answer 1

Have a look at the binary package, or any of its non-lazy variants: cereal or binary-strict .

In all three cases, since you have a specific binary format, I'd ignore the type class Binary defined in each, and instead focus on the Put and Get monads they define.

Answer 2

A perfect job for Data.Binary:

Prelude> :m + Data.Binary
Prelude Data.Binary> encode (pi :: Double)
Chunk "\SOH\SOH\NUL\NUL\NUL\NUL\NUL\NUL\NUL\a\CAN-DT\251!\EM\255\255\255\255\255\255\255\205" Empty

Prelude Data.Binary> encode (42 :: Integer)
Chunk "\NUL\NUL\NUL\NUL*" Empty

to yield lazy bytestrings, which can of course be converted to strict ones. The cereal package provides much the same interface, but yields strict bytestrings only (so no infinite streaming of encodings).