Export list as .txt (Python)

Question

My Python module has a list that contains all the data I want to save as a .txt file somewhere. The list contains several tuples like so:

list = [ ('one', 'two', 'three'), ('four', 'five', 'six')]

How do I print the list so each tuple item is separated by a tab and each tuple is separated by a newline?

Thanks

Answer 1

print '\n'.join('\t'.join(x) for x in L)

Answer 2

Try this

"\n".join(map("\t".join,l))

Test

>>> l = [ ('one', 'two', 'three'), ('four', 'five', 'six')]
>>> print "\n".join(map("\t".join,l))
one     two     three
four    five    six
>>>

Answer 3

open("data.txt", "w").write("\n".join(("\t".join(item)) for item in list))

Answer 4

The most idiomatic way, IMHO, is to use a list comprehension and a join:

print '\n'.join('\t'.join(i) for i in l)

Answer 5

You can solve it, as other answers suggest by just joining lines but better way would be to just use python csv module, so that later on you can easily change delimter or add header etc and read it back too, looks like you want tab delimited file

import sys
import csv

csv_writer = csv.writer(sys.stdout, delimiter='\t')
rows = [ ('one', 'two', 'three'), ('four', 'five', 'six')]
csv_writer.writerows(rows)

output:

one two three
four    five    six

Answer 6

You don't have to join the list in advance:

with open("output.txt", "w") as fp:
    fp.writelines('%s\n' % '\t'.join(items) for items in a_list)