In Linux I would like to run a program but only for a limited time, like 1 second. If the program exceeds this running time I would like to kill the process and show an error message.
you could launch it in a shell script using &
your_program &
pid=$!
sleep 1
if [ `pgrep $pid` ]
then
kill $pid
echo "killed $pid because it took too long."
fi
hope you get the idea, I'm not sure this is correct my shell skills need some refresh :)
If you have the sources, you can fork()
early in main()
and then have the parent process measure the time and possibly kill the child process. Just use standard system calls fork()
, waitpid()
, kill()
, ... maybe some standard Unix signal handling. Not too complicated but takes some effort.
You can also script something on the shell although I doubt it will be as accurate with respect to the time of 1 second.
If you just want to measure the time, type time <cmd ...>
on the shell.
A simple bash-script should be able to do that for you
./myProgram &
sleep 1
kill $! 2>/dev/null && echo "myProgram didn't finish"
That ought to do it.
$!
expands to the last backgrounded process (through the use of &
), and kill returns false if it didn't kill any process, so the echo is only executed if it actually killed something.
2>/dev/null
redirects kill's stderr, otherwise it would print something telling you it was unable to kill the process.
You might want to add a -KILL
or whichever signal you want to use to get rid of your process too.
EDIT
As ephemient pointed out, there's a race here if your program finishes and the some other process snatches the pid, it'll get killed instead. To reduce the probability of it happening, you could react to the SIGCHLD and not try to kill it if that happens. There's still chance to kill the wrong process, but it's very remote.
trapped=""
trap 'trapped=yes' SIGCHLD
./myProgram &
sleep 1
[ -z "$trapped" ] && kill $! 2>/dev/null && echo '...'